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2 years ago

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ASE

Physics

1 answer:

Romashka [77]2 years ago

6 0

$A_x = 5.0$

$A_y = -6.3$

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Answer:

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light of a certain frequency has a wavelength of 438 nm in water.What is the wavelength of this light in benzene

sveticcg [70]

Answer:

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Explanation:

The computation of the wavelength of this light in benzene is shown below:

As we know that

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$\lambda (water) \times n(water) = \lambda (benzene) \times n(benzene)$

And, the wavelength of water is 438 nm

$\lambda (benzene) = \lambda (water) [\frac{n(water)}{n(benzene}]$

Now placing these values to the above formula

So,

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