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Dmitriy789 [7]
3 years ago
12

What do you recall about transformations in a plane? What is important to remember about transformations? What's the difference

between rigid transformations and nonrigid transformations?
Mathematics
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

1)

Any image in a plane could be altered by using different operations, or transformations. Here are the most common types:

  • Translation is when we slide a figure in any direction.
  • Reflection is when we flip a figure over a line.
  • Rotation is when we rotate a figure a certain degree around a point.
  • Dilation is when we enlarge or reduce a figure.

2)

Transformations map one set of points onto another set of points, generally with the purpose of changing the position, size, and/or shape of the figure made up by the first set of points. The first set of points, from the domain of the transformation, is called the set of pre-images, whereas the second set of points, from the range of the transformation, is called the set of images. Therefore, a transformation maps each pre-image point to its image point.

3)

  • A rigid transformation (also called an isometry) is a transformation of the plane that preserves length.

Reflections, translations, rotations, and combinations of these three transformations are "rigid transformations".

  • non-rigid transformations that change the size but not the shape of the preimage.

      example is dilation.  


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Formulas needed:

Square area = b^2
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Triangle area = bh/2
Parallelogram = bh
Trapezoid area = a+b/2(h)
Rhombus area = pq/2

Even better; use online calculators.
To use these formulas, you need to substitute the values given for b,h,a,b,p or/and q and then solve to get area.

So for this example, since it's a rectangle, you use formula A = bh. Base is 5.1, and height is 6.

Substitute now.

A = bh
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   = 30.6       (multiply)

Therefore the area is 30.6 m^2. Don't forget the unit measurements, which is *measurement*^2.
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Answer:

X=-6 y=3

Step-by-step explanation:

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If the circumference is 3/2 pi what is the area
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Here is your answer

\frac{9}{16} \pi \:  {units}^{2}

REASON:

Circumference(C)= 2πr

, where r is radius

Given

C= (3/2) π

So,

2\pi \: r =  \frac{3}{2}\pi

r =   \frac{\frac{3}{2}\pi}{2\pi}

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