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ivanzaharov [21]
3 years ago
14

3^4 x 3^8= 3 to the power of what

Mathematics
1 answer:
Katen [24]3 years ago
6 0

Answer:

3^12

Step-by-step explanation:

When the whole numbers are the same, add the exponents

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The sum of two numbers is 70 and their difference is 24.Find the two numbers
xxMikexx [17]
The two answers are 23 and 47. You would subtract 24 from 70 then divide by 2 which would equal 23 then add the 24 back to it which is 47. 23 plus 47 equals 70.
7 0
3 years ago
Can someone teach me how to solve this please
Alexeev081 [22]
Multiply it all together
7 0
3 years ago
A flower pot weighing 3 newtons is sitting on a windowsill 10 meters from the ground what is its potential energy
krek1111 [17]

Answer:

30 J

Step-by-step explanation:

W = mg = 3 N

h = 10 m

Potential Energy = mgh = 3*10 = 30 J

5 0
2 years ago
The lines y=3x-1 and y=ax+2 are perpendicular if a=___
mezya [45]

Answer:

a = \frac{-1}{3}.

Step-by-step explanation:

The equation of line in the form .

y = mx + c

Where m is the slope and c is the y- intercept .

As given

The lines y=3x-1 and y=ax+2 are perpendicular .

Here 3 is slope for equation of line  y=3x-1 and a is slope for equation of line

y=ax+2 .

Now by using properties of the perpendicular lines property .

When two lines are perpendicular than slope of one line is negative reciprocal of the other line .

Thus

a = \frac{-1}{3}

Therefore a = \frac{-1}{3}.

8 0
3 years ago
Read 2 more answers
Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
Svetlanka [38]

Answer:

The correct options are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Given that RS is parallel to DC, we have;

∠BDC = ∠BRS (Angles on the same side of transversal)

Similarly;

∠BCD = ∠BSR (Angles on the same side of transversal)

∠CBD = ∠CBD = (Reflexive property)

Therefore;

ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency

2) Whereby  ΔBCD ~ ΔBSR, we therefore have;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

Inverting both sides

BR/RD = BS/SC

3) From BR/RD = BS/SC the above we have by cross multiplication;

BR/RD = BS/SC gives;

BR × SC = RD × BR → (BR)(SC) = (RD)(BR).

7 0
2 years ago
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