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sergejj [24]
2 years ago
13

In 2000, in order to reduce the unemployment rate, France mandated all employers with 20 or more employees to reduce the workwee

k to 35 hours. Prior to the new law, the unemployment rate in France was 12%. In a random sample of 500 French workers taken a few years after the new law went into effect, 53 workers were found to be unemployed. Using the p-value method, conduct a hypothesis test to determine if the French unemployment rate dropped after the enactment of the 35- hour workweek law. Assume the significance level as 0.05. (7 Points)
Mathematics
1 answer:
asambeis [7]2 years ago
4 0

Answer:

We accept H₀ for a CI = 95 % we din´t find differences in the unemployment level

Step-by-step explanation:

p₀  = 12 %     p₀  = 0,12

From sample  p = 53/500     p = 0,106

Test Hypothesis

Null Hypothesis                                      H₀                       p = p₀

Alternative Hypothesis                         Hₐ                       p < p₀

p₀*n  = 0,12*500 = 60

q₀ * n = 0,88 * 500 = 440

Then the binomial distribution can be approximate to a normal distribution

The significance level  α = 0,05     CI = 95 %

We need to develop a one-tail test (to the left ) find p-value and compare it with α.

p(s) = ( p - p₀ ) / √ p*q /n

p(s) = 0,106 - 0,12 / √(0,12)*(0,88)/500

p(s) = - 0,014 / 0,015

p(s) = - 0,93

With this P score we find the area under the bell shape curve

p-value = 0,1762 and compare that area with α = 0,05

Then p-value > 0,05

Therefore we accept H₀

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Find the time required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, co
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2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.

Step-by-step explanation:

The given is,

               Initial investment - $5000

               Future amount - $6000

               Interest rate - 7.5% (compounded quarterly)

Step:1

           Formula to calculate the Future amount with compound interest,

                                   F = P(1+\frac{r}{n} )^{nt}...................................(1)

          Where, F - Future amount

                           P - Initial amount

                            r - Rate of interest

                           n - No. of compounding in a year

                            t - Time period

          From given,

                      F = $6000

                      P = $5000

                       r = 7.5%

                       n = 4 (compounded quarterly)

        Equation (1) becomes,

                              6000=5000(1+\frac{0.075}{4} )^{(t)(4)}

                               \frac{6000}{5000} =(1+0.01875)^{4t}

                                 1.2 = (1.01875)^{4t}

         Take log on both sides,

                            log 1.2 = 4(t) log 1.01875

         Substitute log values,

                       0.07918 = 4(t) (0.0080676)

                                      = (t) (0.0322705)

                                   t = \frac{0.07918}{0.0322705}

                                      = 2.45

                                   t ≅ 2.5 years

Result:

         2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.

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