I keep getting questions like this on my assignment and I just don’t understand what it’s asking me to input ?
1 answer:
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Answer:
a) P(three tails) =
b) P(two tails followed by one head) =
Step-by-step explanation:
coin is tossed three times so, outcome is
HHH, TTT, HTH, THH, HHT, THT, TTH, HTT.
Hence sample space will be
S = {HHH, TTT, HTH, THH, HHT, THT, TTH, HTT}
chance of getting three tails is '1' i.e. TTT
hence,
P(three tails) =
two tails followed by one head is TTH
so, chance of getting that outcome is also '1'
hence,
P(two tails followed by one head) =
Answer:
D
Step-by-step explanation:
We have the piecewise function:
And we want to find x such that f(x)=1.
So, let's substitute 1 for f(x):
This has two equations. So, we can separate them into two separate cases. Namely:
Let's solve for x in each case.
Case I:
We have:
Add 1 to both sides:
Let's cancel out the fraction by multiplying both sides by -2. So:
The right side cancels:
Flip:
So, x is -4.
Case II:
We have:
Flip:
This is the solution for our second case.
So, we have:
Now, can check to see if we have to to remove solution(s) that don't work.
Note that x=-4 is the solution to our first equation.
The first equation is defined only if x is less than -2.
-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.
x=1 is the solution to our second equation.
The second equation is defined only if x is greater than or equal to -2.
1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.
Therefore, our two solutions are:
Out of our answer choices, we can pick D.
And we're done!