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3 years ago

Which expression has a value of 3?

Mathematics

2 answers:

VARVARA [1.3K]3 years ago

6 0

(12 + 6) / (3 + 3) =
18 / 6 =
3

ur answer is : (12 + 6) / (3 + 3)

DochEvi [55]3 years ago

3 0

C I think the answer is

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Two linear functions are

Verdich [7]

9514 1404 393

Answer:

Function B has the greater initial value

initial value for Function A is 4

initial value for Function B is 6

Step-by-step explanation:

The initial value for function B is the constant in its equation: 6.

The initial value for function A is the y-value when x=0: 4

The initial value for Function B is greater.

4 0

3 years ago

4(2x - 3) = 6x + 2 Please help fast thankyou

NeTakaya

Answer:

x=7

Step-by-step explanation:

4(2x-3) = 6x+2

8x-12 = 6x+2

2x = 14

x=7

6 0

3 years ago

Solve for c. C = ✓ [?] Enter the number that goes beneath the radical symbol.

igor_vitrenko [27]

Answer:

c = √18

Step-by-step explanation:

You know from the Pythagorean theorem that ...

c² = 3² +3² = 9 +9 = 18

Taking the square root gives ...

c = √18

4 0

3 years ago

According to national data, 5.1% of burglaries are cleared with arrests. A new detective is assigned to six different burglaries

blagie [28]

Answer:

26.95% probability that at least one of them is cleared with an arrest

Step-by-step explanation:

For each burglary, there are only two possible outcomes. Either it is cleared, or it is not. The probability of a burglary being cleared is independent of other burglaries. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5.1% of burglaries are cleared with arrests.

This means that $p = 0.051$

A new detective is assigned to six different burglaries.

This means that $n = 6$

What is the probability that at least one of them is cleared with an arrest?

Either none are cleared, or at least one is. The sum of the probabilities of these events is 100% = 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$

Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.051)^{0}.(0.949)^{6} = 0.7305$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7305 = 0.2695$

26.95% probability that at least one of them is cleared with an arrest

8 0

3 years ago

1/2(n-4)-3=3-2(2n+3

Nataly_w [17]

1/2n-2=3-4n-6

+4n +4n

9/2n-2=-3

+2 +2

9/2n=-1

n=-1*2/9

n=-2/9

7 0

3 years ago