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KonstantinChe [14]

2 years ago

15

PLZ HELP ITS FOR MY EXAM !! What information can the discriminant tell you about a quadratic relation in the form y = ax² + bx +

x?

1 answer:

Romashka [77]2 years ago

7 0

This equals a symmetrical

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Use the figure to find the radius.

BlackZzzverrR [31]

The answer is 4 (four)

3 0

2 years ago

What scale factor was used in the dilation ????? Helpppppp

slava [35]

Answer:

5

Step-by-step explanation:

Dilation = dividing original by (number) to = dilated version.

10/5=2

Dividing 10 by 5 to = 2

(10=original size) (2=dilated size)

8 0

2 years ago

Math Help Please! (Show your work)

Hunter-Best [27]

Hey friend hope it is helpful ......

8 0

2 years ago

Find the point slope equation for the line that passes through the points (1,-9) and (-10,101)

neonofarm [45]

Answer:

( y + 9 ) = -10( x - 1 )

Step-by-step explanation:

First we calculate the slope

$m=\frac{-9-101}{1-(-10)} =-10$

Then we choose a point it could be (1,-9) or (-10,101), I choose (1,-9), the slope point form is (y-y1)=m(x-x1)

( y - (-9) ) = -10( x - 1 )

( y + 9 ) = -10( x - 1 )

it could be also...

( y - 101 )= -10( x- (-10) )

( y - 101 ) = -10( x + 10 )

5 0

2 years ago

Which expression is equivalent to RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Bas

mart [117]

Answer:

Which expression is equal to $\sqrt[3]{64}a^6b^7c^9$ ?

The correct answer is B.

$4a^{2}b^{2}c^{3}(\sqrt[3]{b})$

Step-by-step explanation:

Inside of the radical you have $64a^{6}$ . If you find the cube root of that, you get 4a^2. Go ahead and write that outside of the parenthesis:

$4a^{2}$ $\sqrt[x}$ $\sqrt[3]({b^{7}c^{9}})$

If you re-write what is inside of the radical, you get:

$4a^{2}(\sqrt[3]{b^{3}*b^{3}*b^{1}*c^{3}*c^{3}*c^{3} }$

Basically I expanded what was inside of the radical so I could find the cube roots of b^7 and c^9.

Now, take the cube root of b^7:

$4a^{2}b^{2} (\sqrt[3]b*c^{3}*c^{3}*c^{3} })$

Notice how I could only factor out the two "b^3" that were inside the radical symbol, and how I left the b^1 inside the radical symbol because I couldn't factor it out.

Let's now get the cube root of c^9. Since it's a perfect cube, there won't be any "c"s left inside of the radical symbol:

$4a^{2}b^{2}c^{9}(\sqrt[3]b)$

4 0

2 years ago

Read 2 more answers