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KonstantinChe [14]

3 years ago

15

PLZ HELP ITS FOR MY EXAM !! What information can the discriminant tell you about a quadratic relation in the form y = ax² + bx +

x?

1 answer:

Romashka [77]3 years ago

7 0

This equals a symmetrical

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The spinner is spun 48 times. What is a reasonable prediction of landing on the letter E?

Licemer1 [7]

Answer:

because that is the right amount of times you spun it

Step-by-step explanation:

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3 years ago

A standard number cube with the numbers 1 through 6 is rolled. Find the probability of rolling a number less than 3

pav-90 [236]

1/3, because the probability in the cube is 1/6, and there are 2 numbers less than 3. So, 2/6 and simplify 2/6 to 1/3.

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4 years ago

Jerry makes $300 per month but always runs out of money. He has $85 in fixed expenses and $60 in variable expenses that must be

cupoosta [38]

Answer: 155

Step-by-step explanation:

$300-$85-$60= $155

3 0

3 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: <em>rational equation fraction solution algebra</em>

7 0

3 years ago

7^2 + 3[81 – (4x6)] please help me!!!!!!!!

Anastaziya [24]

Answer:220

Step-by-step explanation:Simplify

4 0

3 years ago