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ludmilkaskok [199]
3 years ago
13

Two of the three views of a solid are shown. A. What is the greatest number of unit cubes in the solid? Greatest number of unit

cubes: cubes b. What is the least number of unit cubes in the solid? Least number of unit cubes: cubes Question 2
Mathematics
1 answer:
scoray [572]3 years ago
5 0

Answer: hello the views attached to your question is missing hence I will provide a more general answer based on the scope of your question

answer :

a) 8 unit cubes

b) 1 unit cube

Step-by-step explanation:

The number of views a solid figure can have are : Top view , Front view and side view  and The greatest number of unit cubes in a solid depends on the side length of the unit cube

a) For a unit cube with side length half ( 1/2) the Unit length of the given solid the greatest number of unit cubes = 8  while

b) The least number of unit cube = 1  

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A room has a length of 8 m. A scale diagram is drawn of the room. In the diagram, the room has a length of 1 cm. What is the sca
liberstina [14]

The scale of the diagram as described in the task content is; 1: 8 where k= 8.

<h3>What is the scale of the diagram?</h3>

It follows from the task content that the original length of the room in discuss is 8cm. It therefore follows that the length of the room in the scale diagram is 1cm. On this note, the scale of the diagram in discuss is; 1 : 8 as 1cm on the diagram corresponds to 8cm actual length.

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8 0
2 years ago
Arrange the numbers in decreasing order<br> 9/4 <br> 2 1/12<br> 2 1/2<br> 12/11
LekaFEV [45]
2 1/2
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12/11
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3 0
4 years ago
If a 100.8 kg cement bag had 20.35 kg removed from it, what is the new weight of the bag?
Snowcat [4.5K]
Just subtract 20.35 from 100.8
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if your bag weighs 100.8 kg and you scoop out 20.35 kg then weigh your bag it will be 80.45 bc u took out 20.35 kg of the cement to use. hope that explains it
8 0
3 years ago
Tan 45°. tan² 30° tan 60° <br>slove it​
makvit [3.9K]

Answer:

\frac{\sqrt{3} }{3} or \frac{1}{\sqrt{3} }

Step-by-step explanation:

We can break the problem into three parts,

tan45 = sin(45)/cos(45)=\frac{\frac{\sqrt{2}}{2} }{\frac{\sqrt{2}}{2} } =1

tan^{2}30 =(tan30))^{2}=(sin30/cos30)^2=((1/2)/(\sqrt{3}/2))^2 =(1/\sqrt{3})^2

tan60=sin60/cos60=\frac{\sqrt{3}/2 }{1/2} =\sqrt{3}

Then, tan45*tan^230*tan60=1*(1/sqrt(3))^2*sqrt(3)=1/sqrt(3)=sqrt(3)/3

Therefore, the solution is sqrt(3)/3

4 0
2 years ago
In the diagram, a building casts a 20-ft shadow and a flagpole casts a 7-ft shadow. If the flagpole is 12 ft tall, how high is t
andriy [413]
12/7 = x/20 
<span>7x = 240 </span>
<span>x = 34.3 ft

</span>
6 0
4 years ago
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