PLEASE HELP ME I'LL FAIL MATH 20 POINTS
2 answers:
Answer:
1.a.
2.d=
3.c.
4.c.The quotient of some number and six.
5.a.The quotient of three times some number and five
6.b.
Step-by-step explanation:
1.We are given that verbal expression ''five times the difference of a number and six''
We have to find its algebraic expression
Let x be the number
Difference of x and 6=x-6
We are multiplying difference of x and 6 by 5
Then we get
Option a is true
2.Verbal expression ''nine less than some number ''
Let k be the some number
Nine less than some number k
=
Option d is true.
3.Five more than the product of ten and some number .
Let x be the some number
Product of 10 and some number x
Then we get 10 x
Now, 5 more than the product of 10 and x
Then, we get an algebraic expression
Hence, option c is true.
4.Given algebraic expression
Fraction with variable x in numerator and 6 in the denominator .
We have to find its verbal expression
The quotient of some number and six.
Hence, option c is true.
5.We are given that an algebraic expression
We have to find its verbal expression
The quotient of three times some number and five
Where x is some number in algebraic expression.
Hence, option a is true.
6.We are given that verbal expression
''Some number to the power of 5''
We have to find the algebraic expression
Let x be the some number
Then , the algebraic expression
Hence, option b is true.
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Answer:
Rebecca and Dan need to ride on the third day in order to achieve goal of biking.
Step-by-step explanation:
Given:
Goal of Total number of hours of biking in park =20 hours.
Number of hours rode on first day =
So we will convert mixed fraction into Improper fraction.
Now we can say that;
To Convert mixed fraction into Improper fraction multiply the whole number part by the fraction's denominator and then add that to the numerator,then write the result on top of the denominator.
can be Rewritten as
Number of hours rode on first day =
Also Given:
Number of hours rode on second day =
can be Rewritten as
Number of hours rode on second day =
We need to find Number of hours she need to ride on third day in order to achieve the goal.
Solution:
Now we can say that;
Number of hours she need to ride on third day can be calculated by subtracting Number of hours rode on first day and Number of hours rode on second day from the Goal of Total number of hours of biking in park.
framing in equation form we get;
Number of hours she need to ride on third day =
Now we will use LCM to make the denominators common we get;
Number of hours she need to ride on third day =
Now denominators are common so we will solve the numerator we get;
Number of hours she need to ride on third day =
Hence Rebecca and Dan need to ride on the third day in order to achieve goal of biking.