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mash [69]
3 years ago
14

HOW MUCH WATER PUMPS CAN IT PUMP IN ONE MINUTES PLEASEE HELP I NEED TO DO NOWWp

Mathematics
1 answer:
zimovet [89]3 years ago
5 0
50 pumps of water is the answer
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The scale factor of the blueprint of a garage door to the actual garage door is 0.05. the are of the actual garage door is 220 f
erastovalidia [21]
The scale factor 0.05 refers to length, so for area the scale factor is 0.05²=0.0025.

We then multiply: 220 ft²*0.0025=0.55 ft² (choice A)
8 0
3 years ago
Read 2 more answers
A triangle has a perimeter of 90 centimeters write and use a linear system
lawyer [7]

We are given sides of the triangle by expression

First side : n

Second side : m = 5n-5.

Third side : l = 5/4 m - n.

Perimeter is 90.

Therefore, first equation could be set :

n +m +l = 90   --------------equation(1)

Second equation would be

m = 5n-5        --------------equation(2)

Third equation would be

l = 5/4 m - n   --------------equation(3)

Let us solve the system of equations by substitution.

Substituting m = 5n-5 and l = 5/4 m - n in first equation.

We get

n +5n-5 +5/4 m - n= 90

Now, substituting m = 5n-5 in above equation we get

n +5n-5 +5/4 (5n-5) - n= 90

5n + 25n/4 -5 - 25/4 =90

5n + 6.25n -5-6.25 = 90.

11.25n-11.25 = 90

Adding 11.25 on both sides, we get

11.25n-11.25+11.25 = 90+11.25

11.25n = 101.25.

Dividing both sides by 11.25, we get

n=9.

Plugging n=9 in 2nd equation.

m = 5(9)-5 = 45 -5 = 40.

Plugging n=9 and m=40 in first equation, we get

9 +40 +l = 90

49 +l = 90.

Subtracting 49 from both sides, we get

49-49 +l = 90-49

l = 41.

Therefore, sides are of lengths l = 41, m= 40 and n=9.


5 0
3 years ago
A _______________________ is a comparison of two measurements in which the denominator has a value of one unit.
Galina-37 [17]
I think the answer is unit rate.
8 0
3 years ago
What the value of r that makes the value true? r+(-0.14)=0.47
siniylev [52]

r+(-0.14)=0.47\\\\r-0.14=0.47\qquad|\text{add 0.14 to both sides}\\\\r-0.14+0.14=0.47+0.14\\\\r=0.61

4 0
3 years ago
In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta
Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.3246

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0
2 years ago
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