Help please and thank you

Mathematics

1 answer:

kramer2 years ago

3 0

The altitude to the hypotenuse of a right triangle is the mean proportional between the segments into which it divides the hypotenuse ⇒<span>

</span>altitude = √(9*3) = √27

<span>By the Pythagorean theorem:

y = </span>√(9² + (√27)²) = √(81+27) = √108 = 6√3 ← answer

You might be interested in

4-[6(3x+2)-x]+4 order of operations

weqwewe [10]

Answer:

-4 - 17x

Step-by-step explanation:

Anything enclosed in parentheses must be done first if possible. (3x + 2) is inside two sets of parentheses, but nothing can be done with 3x + 2.

Multiplication must be done next. [6(3x+2)-x] becomes 18x + 12 - x, or

17x + 12.

Now we have 4 - 17x - 12 + 4. Combining like terms through addition and subtraction, we get 4 - 12 + 4 - 17x, or -4 - 17x.

3 0

3 years ago

emma gave 2/5 of her money and an additional $9 to olivia. she gave 4/7 of her remaining money and an additional $1 to Ava. emma

alexandr1967 [171]

Yo wsp how is it going kane

5 0

2 years ago

Read 2 more answers

A doctor released the results of clinical trials for a vaccine to prevent a particular disease. In these clinical trials, 200,0

CaHeK987 [17]

Answer:

1) No, there is not enough evidence to support the claim that the vaccine was effective (P-value=0.104) .

The null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

being the subindex 1 for the experimental group and subindex 2 for the control group.

2) Test statistic z=-1.26

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the vaccine was effective.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

The significance level is 0.01.

The sample 1 (experimental group), of size n1=100000 has a proportion of p1=0.0002.

$p_1=X_1/n_1=21/100000=0.0002$

The sample 2 (control group), of size n2=100000 has a proportion of p2=0.0003.

$p_2=X_2/n_2=30/100000=0.0003$

The difference between proportions is (p1-p2)=-0.0001.

$p_d=p_1-p_2=0.0002-0.0003=-0.0001$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{21+30}{100000+100000}=\dfrac{51}{200000}=0.00026$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.00026*0.99974}{100000}+\dfrac{0.00026*0.99974}{100000}}\\\\\\s_{p1-p2}=\sqrt{0+0.0000000025}=\sqrt{0.0000000051}=0.000071$