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2 years ago

Help please and thank you

Mathematics

1 answer:

kramer2 years ago

3 0

The altitude to the hypotenuse of a right triangle is the mean proportional between the segments into which it divides the hypotenuse ⇒

altitude = √(9*3) = √27

By the Pythagorean theorem:

y = √(9² + (√27)²) = √(81+27) = √108 = 6√3 ← answer

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7x - 2 = 2y 3x = 2y - 1

77julia77 [94]

7x - 2 = 2y
7x = 2y + 2
so
7x = 2y + 2
3x = 2y - 1
----------------subtract
4x = 3
x = 3/4

7x - 2 = 2y
7(3/4) - 2 = 2y
21/4 - 2 = 2y
21/4 - 8/4 = 2y
13/4 = 2y
so
y = 13/4 * 1/2
y = 13/8

answer
(3/4, 13/8)

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3 years ago

What is the remainder for 89,736 divided by 40?

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Answer: 2,243.4

Step-by-step explanation:

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3 years ago

6ft to 6yd in unit rate

luda_lava [24]

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3 years ago

For each value of u, determine whether it is a solution to -15 = 1 - 4u

Alona [7]

Answer:

1. No

2. No

3. No

4. Yes

Step-by-step explanation:

Plug each option into u then solve the equation and see if the answer matches -15.

Ex. -15 = 1 -4 (2)

-15 = 1 -8

-15 = -7

-15 does not equal -7 therefore it is false. Use Pemdas to solve.

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3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):