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Artist 52 [7]
3 years ago
9

2. The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

Mathematics
1 answer:
Paul [167]3 years ago
8 0
For this case we have an equation of the form:
 h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
 Where,
 vo: initial speed
 a: acceleration:
 h0: initial height.
 We have the following equation:
 h (t) = - 16t2 + 19t + 110
 Therefore, the initial velocity is:
 vo = 19 feet / s
 Answer:
 
The initial velocity when the rock is thrown:
 
vo = 19 feet / s
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