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Lerok [7]
3 years ago
11

What is the theoretical probability of rolling a number less than 5? Write the fraction, decimal and percent.

Mathematics
1 answer:
stealth61 [152]3 years ago
8 0

Given:

Rolling a fair dice.

To find:

The theoretical probability of rolling a number less than 5.

Solution:

The possible numbers of rolling a dice are 1, 2, 3, 4, 5, 6.

Total outcomes = 6

Numbers less than 5 are 1, 2, 3, 4.

Favorable outcomes = 4

Now, the theoretical probability of rolling a number less than 5 is:

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

\text{Probability}=\dfrac{4}{6}

\text{Probability}=\dfrac{2}{3}

In decimal form, it can be written as:

\text{Probability}\approx 0.67

In percentage form, it can be written as:

\text{Probability}=\dfrac{2}{3}\times 100

\text{Probability}\approx 66.67%

Therefore, the theoretical probability of rolling a number less than 5 in the fraction, decimal and percent are \dfrac{2}{3}, 0.67 and 66.67\% respectively.

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Mitra used 156 white tiles of 2x2 cm and 76 black tiles of 2x3 cm to form a pattern with an area of 1092 cm²

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the number of white tiles and y represent the number of black tiles.

Area of white tiles = 2 cm * 2 cm = 4 cm²

Area of black tiles = 2 cm * 3 cm = 6 cm²

She used twice as many white tiles as black tiles. Hence:

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From both equations:

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3 0
2 years ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

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Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

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x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

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