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notka56 [123]
3 years ago
12

How many 3/4 -foot pieces of yarn can be cut from 24 feet of yarn?

Mathematics
1 answer:
12345 [234]3 years ago
3 0

Answer get 6 4 feet piece and you can get

and 8 3 feet pieces

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G=h(t) + p(c) is an equation that represents the gross pay of a server: Gross pay = hourly wage (time worked) + percent tip (cos
rusak2 [61]

Answer:

$105.5  for 16 hours at $6.59 per hour

Step-by-step explanation:

form the equation given, G=h(t) + p(c)

where G=Gross pay,

            h= hourly wage

            t=time worked

             p=percent tip

             c=cost of customer meals

we determine the gross pay by first determining the independent variables

h=$4.25, t=16 hours,

p=15%of c\\p=\frac{15}{100}*250 \\p=37.5

if we substitute values, we arrive at

G=h(t)+p(c)\\G=4.25(16)+37.5\G=68+37.5\\G=105.5

to determine the per hour gross pay we have

105.5/16

hourly gross pay,G=$6.59

3 0
3 years ago
ashley spent half of her weekly allowance playing mini golf. to earn more money her parents let her wash the car for $9. what is
Murrr4er [49]
Her allowance is $12.
6 0
4 years ago
Read 2 more answers
Write your answer as a decimal or whole number
Olin [163]

Answer:

4.3

Step-by-step explanation:whats the answers?

and what is the question

5 0
3 years ago
Read 2 more answers
Find <img src="https://tex.z-dn.net/?f=a_%7B1%7D" id="TexFormula1" title="a_{1}" alt="a_{1}" align="absmiddle" class="latex-form
yKpoI14uk [10]

Answer:

\displaystyle  a_{1}    = 108

Step-by-step explanation:

we are given

the sum,common difference and nth term of a geometric sequence

we want to figure out the first term

recall geometric sequence

\displaystyle S_{ \text{n}} =  \frac{ a_{1}(1 -  {r}^{n} )}{1 - r}

we are given that

  • S_n=189
  • r=\dfrac{1}{2}
  • n=3

thus substitute:

\displaystyle 189=  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{1 -  \frac{1}{2} }

to figure out a_1 we need to figure out the equation

simplify denominator:

\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{ \dfrac{1}{2}  }  = 189

simplify square:

\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{8} )}^{} )}{ \dfrac{1}{2}  }  = 189

simplify substraction:

\displaystyle  \frac{ a_{1} (\frac{7}{8} )}{ \frac{1}{2}  }  = 189

simplify complex fraction:

\displaystyle   a_{1} (\frac{7}{8} ) \div { \frac{1}{2}  }  = 189

calculate reciprocal:

\displaystyle   a_{1} \frac{7}{8}   \times 2  = 189

reduce fraction:

\displaystyle   a_{1} \frac{7}{4}   \  = 189

multiply both sides by 4/7:

\displaystyle   a_{1} \frac{7}{4}  \times  \frac{4}{7}   \  = 189 \times  \frac{4}{7}

reduce fraction:

\displaystyle   a_{1}     = 27\times  4

simplify multiplication:

\displaystyle  a_{1}    = 108

hence,

\displaystyle  a_{1}    = 108

4 0
3 years ago
Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
Tatiana [17]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
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