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victus00 [196]
3 years ago
6

The total cost of a shirt and an $8 pair of socks

Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0

Answer:

$28 $20 is average shirt price

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I need an explanation so I can understand this because am very confused
Goryan [66]

Answer:

Doesn’t go though origin

Step-by-step explanation:

It’s non proportional because the line doesn’t go though (0,0) being the origin

hope this helped :)

(if you still don’t understand ill try to explain further in the comments)

8 0
3 years ago
-4x^2+20-4 in standard form
oksian1 [2.3K]
The answer should be -4x^2+16               
4 0
3 years ago
Does anyone know know to do this ?
Rus_ich [418]
He drinks 8 glasses of water in one day. to know the number of glasses he drinks in 365 days, simply use cross multiplication as follows:
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so, yes his assumption is reasonable if he kept the same rate (8 glasses per day each day)
7 0
3 years ago
Abigail has a green,yellow,and purple shirt to mach with either a white,black,or red pair of pants.How many different shirt and
givi [52]
Hahaha Well actually u just have to multiply MY mummy always helps me with math like that
7 0
2 years ago
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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