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snow_lady [41]
1 year ago
5

Luna is making a rope ladder. Each step of the ladder is 2 1/3 feet wide and uses an additional 1/2 foot on each end of the step

for the knot. Luna has a rope that is 30 feet long. How many steps can she make from the rope?
Mathematics
1 answer:
koban [17]1 year ago
6 0

By taking the quotient between the total length and the length needed for each step, we conclude that Luna can make 9 steps.

<h3>How many steps can she make from the rope?</h3>

To find this, we need to take the quotient between the total length of the rope and the length needed for each step.

She has a total length of 30ft.

For each step she needs (2 + 1/3) ft plus (1/2) ft for each knot, and there are two knots, then each step needs: (2 + 1/3)ft + 2*(1/2)ft = (3 + 1/3) ft.

Then the number of steps that can be made is:

N = (30 ft)/(3 + 1/3) ft. = 9

She can make 9 steps or the lader.

If you want to learn more about quotients:

brainly.com/question/8952483

#SPJ1

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(Geometry)<br> Could anyone help me with this please and thanks
Ket [755]

Answer:

z = 32/3

Step-by-step explanation:

Presuming all the horizontal lines are parallel, the ratios of lengths will be identical.

3/8 = 4/z

3z = 8(4)

z = 32/3

8 0
3 years ago
The ratio of pencil to rulers is 6:10. the are 21 pencils. how many rulers are there
Reika [66]

There would be 35 rulers.

In order to solve this, use cross multiplication.

6/10 = 21/x -----> cross multiply

10*21 = 6*x

210 = 6x

35 = x

8 0
3 years ago
Math help please i have discalcula
user100 [1]

Answer:

x=4y,3x=4y,y=4x,4x=3y

5 0
3 years ago
The A&amp;M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0
3 years ago
the volume of a cone is 120 cubic centimeters. the height of the cone is 4.5 centimeters. determine the radius of a cone
kolbaska11 [484]
<h3> given:</h3>

<u>v = 120 \:  {cm}^{3}</u>

<u>h = 4.5 \: cm</u>

<h3>to find:</h3>

the radius of the cone.

<h3>solution:</h3>

r =  \sqrt{3 \frac{v}{\pi \: h} }

r =  \sqrt{3  \times   \frac{120}{\pi \times 4.5} }

r = 5.04627 \: cm

r = 5.05 \: cm

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cone</u><u> </u><u>is</u><u> </u><u>5.05</u><u> </u><u>centimeters</u><u>.</u>

7 0
2 years ago
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