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-Dominant- [34]
3 years ago
6

Does the sequence 120,90,60,30..... converge or diverge?

Mathematics
2 answers:
Olenka [21]3 years ago
8 0
The sequence conveges
jekas [21]3 years ago
4 0
Solutions 

<span>The sequence 120,90,60,30..... converges. </span>
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http://www.calculator.net/surface-area-calculator.html
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3 years ago
An integer is between -4 and -19. It is twice as far from -4 as it is from -19. What is the integer? SHOW ALL YOUR STEPS**
ohaa [14]

Answer:

-12

Step-by-step explanation:

use a number line go back 8 spaces from 19 and back from negative 4

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3 years ago
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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the​ plate, including t
vredina [299]

You're looking for the extreme values of x^2+3y^2+13x subject to the constraint x^2+y^2\le1.

The target function has partial derivatives (set equal to 0)

\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2

\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0

so there is only one critical point at \left(-\dfrac{13}2,0\right). But this point does not fall in the region x^2+y^2\le1. There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of x^2+y^2\le1 by

x=\cos u

y=\sin u

with 0\le u. Then t(x,y) can be considered a function of u alone:

t(x,y)=t(\cos u,\sin u)=T(u)

T(u)=\cos^2u+3\sin^2u+13\cos u

T(u)=3+13\cos u-2\cos^2u

T(u) has critical points where T'(u)=0:

T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0

(1)\quad\sin u=0\implies u=0,u=\pi

(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4

but |\cos u|\le1 for all u, so this case yields nothing important.

At these critical points, we have temperatures of

T(0)=14

T(\pi)=-12

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0
3 years ago
Which function is (x-3) a real root?
uranmaximum [27]
Number 333333333333333333333333
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3 years ago
3 folders cost $2.91 dollar sign . Which equation would help determine the cost of 2 folders? WRITE THE LETTER IN THE SPACE BELO
Anna11 [10]

Answer:

$1.94

Step-by-step explanation:

Cost of 3 folders = $2.91

We need to find the cost of 2 folders.

First we will find the cost of 1 folder

1 folder = $2.91/3 = $0.97

To find the cost of 2 folders, multiply $0.97 and 2

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= $1.94

Hence, the cost of 2 olders is $1.94.

3 0
2 years ago
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