D + q = 110......d = 110 - q
0.10d + 0.25q = 20.30
0.10(110 - q) + 0.25q = 20.30
11 - 0.10q + 0.25q = 20.30
-0.10q + 0.25q = 20.30 - 11
0.15q = 9.30
q = 9.30/0.15
q = 62 <==== there are 62 quarters
d = 110 - q
d = 110 - 62
d = 48 <==== there are 48 dimes
Answer:
51.63m^3
Step-by-step explanation:
The figure is made up of a rectangle, triangle and a semi circle
Area of the figure = Area of triangle + rectangle + semicircle
Area of the triangle = 1/2 * base * height
Area of the triangle = 1/2 * 3 * 5
Area of the triangle = 15/2
Area of the triangle = 7.5m^3
Area of the rectangle = Length * Width
Area of the rectangle = 6 * 5
Area of the rectangle = 30m^2
Area of the semicircle = πr²/2
Area of the semicircle = π(3)²/2
Area of the semicircle = 3.14(9)/2
Area of the semicircle = 3.14 * 4.5
Area of the semicircle = 14.13m^2
The area = 30 + 14.13+7.5
Area of the figure = 51.63m^3
Answer:
950
Step-by-step explanation:
The common difference is 4, so the general term can be written:
... an = 14 + 4(n -1)
The value of n for the last term is ...
... 86 = 14 + 4(n -1) . . . . . the computation for the last term, 86
... 72 = 4(n -1) . . . . . . . . . subtract 14
... 18 = n -1 . . . . . . . . . . . divide by 4
... 19 = n . . . . . . . . . . . . . add 1
Your series has 19 terms. The first term is 14 and the last is 86, so the average term is (14+86)/2 = 50. Since there are 19 terms, the sum of them is ...
... 19×50 = 950
The equation is put in slope intercept form which is y=mx+b
The slope is m and in this case it is -1/2.
To find the y intercept substitute in 0
for x then solve.
