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olchik [2.2K]
3 years ago
15

If you travel at a rate of 45 miles per hour, how many minutes will it take you to travel 1 mile

Mathematics
1 answer:
gavmur [86]3 years ago
8 0
1 minute and 15 seconds.
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What is the value of (3-5)*(2) — 16- 2?<br> -40<br> 0 -16<br> ооо<br> 24<br> 56
valina [46]

if i didn't understand it wrong, * is (3-5) x (2)

so,

(3-5)x 2-16-2

=-2x2-16-2

=-4-16-2

= -22

But if * means (3-5)^2 -16-2

then its,

(3-5)^2-16-2

=(-2)^2 -18

=4-18

= - 14

But looks like both of them are not in your choice at all

4 0
3 years ago
Consider the accompanying set of dependent and independent variables. The variable x3 is qualitative with H=​High, M=​Medium, an
Dominik [7]

Answer:

Y = 6.6406 + 0.2068x2 + 0.7995x3 - 3.607x4

Step-by-step explanation:

y 63 53 77 53 38 43 34 20 13

x1 45 42 40 37 27 24 20 14 12

x2 74 62 80 53 42 48 35 16 13

x3 H H L M H M L L M

For regression analysis : all variables must be quantitative ;

X3 variable may be represented as thus;

L = 1 ; M = 2 ; H = 3

Hence ;

X3 = 3 3 1 2 1 2 1 1 2

y= ____ + (____)x2+ (____)x3 + (____)x4

Using the online multiple regression calculator :

Y = 6.6406 + 0.2068x2 + 0.7995x3 - 3.607x4

From the general formular of a linear model:

y = w1x1 + w2x2 +... + wnxn + c = 0

Where c = intercept

w1,.. wn = weight of explanatory variable

Hence, the weights of x2 = 0.2068

Weight of x3 = 0.7995

Weight of x4 = - 3.607

Intercept = 6.6406

5 0
3 years ago
PLEASE HELP IN IMAGE nonsense will be reported
Degger [83]
The answer is -2. The line is going from left to right which makes it negative. Then if you look at the line and do change in y(rise) over change in x(run).
8 0
3 years ago
Given f(x) = x^2-2x+5<br> Find f(-2)
lbvjy [14]

Answer:

<h2>f(-2) = 13</h2>

Step-by-step explanation:

f(x) = x² - 2x + 5

Yo find f(-2) substitute the value of x that's - 2 into f(x) that is for every x in f (x) replace it with - 2

So we have

f( - 2) = (-2)² - 2(-2) + 5

= 4 + 4 + 5

= 8 + 5

We have the final answer as

<h3>f(-2) = 13</h3>

Hope this helps you

7 0
3 years ago
*plz help it’s due tomorrow:)
ra1l [238]

Answer:

  • <em>The actual temperature after the freezer was on for five minutes could be </em><u><em>18ºF or 12ºF</em></u>

Explanation:

First, you must find the y-value returned by the line in the graph for a time (x) of five minutes, and then use the deviation of 3º to conclude the range of the real temperature.

<u>1. y- value at x = 5 min.</u>

The trend line (blue line in the graph) passes through the point (5,15), which means that it predicts a temperature of 15ºF when the time (x) is 5 minutes, or five minutes after the freezer was turned on.

<u>2. Actual temperature value</u>

It is stated that the temperature was actually three degrees from what the trend line shows, that means that the actual temperature could be 3ºF more or 3ºF less than the predicted temperature of 15ºF.

Mathematically:

  • Temperature = 15ºF ± 3ºF

  • Temparature = 15ºF + 3ºF or 15ºF - 3ºF

  • Temperature = 18ºF or 12ºF ← answer.
8 0
4 years ago
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