Hello from MrBillDoesMath!
Answer: 5n - 2
where "n" is the number mentioned in the problem statement
Thank you,
MrB
Is it like this?
y=-4+8
y=4
Is this what you need?
Answer:
1 \times \frac{3}{5} + ( \frac{7}{10} )
Answer:
10×10=100 I really hope this was a joke
Answer:
Minimum total cost = $20550
maximum revenue $44,100
Step-by-step explanation:
Given data:
Production cost $5.55 per unit
Fixed cost = $15000 per month
Price, p = 42-0.01 q
where. q represent number of unit produced
revenue can be wriiten as
p.q = 42q - 0.01q^2
1) from information 1000 unit has to produced therefore
total cost = 15000 + 5.55×1000 = $20550
Minimum total cost = $20550
2) Revenue = 42q - 0.01q^2
therefore for maximum revenue q is = 2100
so, maximum revenue
= $44,100