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Soloha48 [4]
3 years ago
10

Answer the question please and don't guess whoever gets it right will be brainlyest

Mathematics
2 answers:
kiruha [24]3 years ago
6 0
100/1 is the probability
denpristay [2]3 years ago
5 0
1/1 duh xD ........................
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1.5/4x+1=0.4/x+4 PLEASE HELP ITS PROPORTIONS
Serhud [2]

Answer:

Proportion states that the two fractions or ratios are equal

Given the equation:  \frac{1.5}{4x+1} = \frac{0.4}{x+4}

By cross multiply we get;

1.5(x+4) = 0.4(4x+1)

Using distributive property; a\cdot (b+c) = a\cdot b+ a\cdot c

1.5x + 6= 1.6x + 0.4

Subtract 0.4 from both sides we get;

1.5x +5.6= 1.6x

Subtract 1.5x from both sides we get;

5.6= 0.1x

Divide both sides by 0.1 we get;

x = \frac{5.6}{0.1}

Simplify:

x = 56

Therefore, the value of x that satisfy the equation \frac{1.5}{4x+1} = \frac{0.4}{x+4} is, 56

5 0
3 years ago
Help asap will give BRAINLIEST
dybincka [34]

The answer: d. < 1 and < 8

5 0
3 years ago
Randy said that the number 0.03 has a value 10 times greater than 0.003 is he correct.
pishuonlain [190]
Yes, he is correct. 0.003 * 10 = 0.03
5 0
3 years ago
Enter the exponents for the variables of the GCF of the following monomials.
miskamm [114]
The smallest exponents of the x and y term are 2. The Greatest Common Factor ( G C F ) for 9 x² y² and 5 x² y³ is:  x² y².
8 0
3 years ago
Read 2 more answers
An observation deck extends 202 feet out above the valley. The deck sits 152 feet above the valley floor. If an object is droppe
OleMash [197]

Answer:

<h3>3 secs</h3>

Step-by-step explanation:

Given the height of the object as it drops from the observation deck expressed as;

h= -16t^2+152

To determine the the time it will take the object to be 8 feet above the valley floor, we will substitute h = 8 into the equation and calculate t as shown;

8 = -16t^2+152

subtract 8 from both sides

8-8 = -16t^2+152-8

0 =  -16t^2+144

0-144 =  -16t^2

-144 = -16t^2

16t^2 = 144

Divide both sides by 16;

16t^2/16 = 144/16

t^2 = 9

t = √9

t = 3seconds

Hence it will take 3 seconds for the object to be 8 feet above the valley floor

6 0
3 years ago
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