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Oksanka [162]
3 years ago
7

The city wants to build a football field. Each wheelbarrow full of dirt covers an area of. Determine how many wheelbarrows full

of dirt they need for the field below.

Mathematics
1 answer:
lesya692 [45]3 years ago
6 0

Answer: 5x^{2}+45x


Step-by-step explanation:

1. First, you must calculate the area of the football field. It is a rectangle, therefore, multiply the lenght by the width to calculate the area:

Area=lenght*width\\Area=(10x^{2}+90x)5x^{2}\\Area=50x^{4}+450x^{3}

2. Then, divide this area by the area covered by a wheelbarrow full of dirt.

x: number of wheelbarrows full of dirt needed for the field.

x=\frac{50x^{4}+450x^{3}}{10x^{2}}=5x^{2}+45x


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A student can pitch a fast ball at 65 miles per hour. Convert this
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31.77 yd/sec

Step-by-step explanation:

<u>Conversions:</u>

  • 1 mile = 1760 yards
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<u>Given:</u>

\sf 65\:miles\:per\:hour=65\:miles/hour=\dfrac{65\:miles}{hour}

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6 0
1 year ago
Read 2 more answers
Part B
SVEN [57.7K]

Answer:

$500

Step-by-step explanation:

substitute the values for X & S in the equation from part A:

y=20x + 0.15s

x=($20x25) + (0.15x$0)

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3 0
3 years ago
Part 4: Identify the vertex, focus and directrix of each. Then sketch the graph.
Nezavi [6.7K]

Answer: 1) Vertex: (6, -2)    Focus: (6, -7/4)     Directrix: y = -9/4

              2) Vertex: (-2, -1)   Focus: (-7/4, -1)     Directrix: x = -9/4

<u>Step-by-step explanation:</u>

Rewrite the equation in vertex format y = a(x - h)² + k   or   x = a(y - k)² + h by completing the square. Divide the b-value by 2 and square it - add that value to both sides of the equation.

  • (h, k) is the vertex
  • p is the distance from the vertex to the focus
  • -p is the distance from the vertex to the directrix

    \bullet\quad a=\dfrac{1}{4p}

1) y = x² - 12x + 34

y-34=x^2-12x\\\\y-34+\bigg(\dfrac{-12}{2}\bigg)^2=x^2-12x+\bigg(\dfrac{-12}{2}\bigg)^2\\\\\\y-34+36=(x-6)^2\\\\y+2=(x-6)^2\\\\y=(x-6)^2-2\qquad \rightarrow \qquad a=1\quad (h,k)=(6,-2)\\

a=\dfrac{1}{4p}\quad \rightarrow \quad 1=\dfrac{1}{4p}\quad \rightarrow \quad p=\dfrac{1}{4}\\\\\\\text{Focus = Vertex + p}\\.\qquad \quad =\dfrac{-8}{4}+\dfrac{1}{4}\\\\.\qquad \quad =-\dfrac{7}{4}\quad \rightarrow \quad\text{Focus}=\bigg(6,-\dfrac{7}{4}\bigg)\\\\\\\text{Directrix: y= Vertex - p}\\.\qquad \qquad y=\dfrac{-8}{4}-\dfrac{1}{4}\\\\.\qquad \qquad y=-\dfrac{9}{4}

*******************************************************************************************

2) x = y² + 2y - 1

x+1=y^2+2y\\\\x+1+\bigg(\dfrac{2}{2}\bigg)^2=y^2+2y+\bigg(\dfrac{2}{2}\bigg)^2\\\\\\x+1+1=(y+1)^2\\\\x+2=(y+1)^2\\\\x=(y+1)^2-2\qquad \rightarrow \qquad a=1\quad (h,k)=(-2,-1)\\

a=\dfrac{1}{4p}\quad \rightarrow \quad 1=\dfrac{1}{4p}\quad \rightarrow \quad p=\dfrac{1}{4}\\\\\\\text{Focus = Vertex + p}\\.\qquad \quad =\dfrac{-8}{4}+\dfrac{1}{4}\\\\.\qquad \quad =-\dfrac{7}{4}\quad \rightarrow \quad\text{Focus}=\bigg(-\dfrac{7}{4},-1\bigg)\\\\\\\text{Directrix: x= Vertex - p}\\.\qquad \qquad y=\dfrac{-8}{4}-\dfrac{1}{4}\\\\.\qquad \qquad x=-\dfrac{9}{4}

4 0
3 years ago
C) 40.3, 32.7, 40.29, 43.43,<br>32.23 In Decreasing order please ​
iogann1982 [59]

Answer:

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Step-by-step explanation:

Hope this helps =)

Correct me if I am wrong

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