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3 years ago

2sin^(-2490)+tan 1410

1 answer:

7 0

2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6

Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)

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Autumn found a wallet containing $ 900 in the street. She returned the wallet to its owner, who gave her a $ 180 reward. What pe

Murljashka [212]

Answer:

$\frac{180}{900} = 0.2$ × $100 =20$

Autumn got a 20% reward of the $900 she found.

4 0

3 years ago

Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.

Dimas [21]

Answer:

The nonzero value of c will be:

$c = 6$

Step-by-step explanation:

Given the function

$f\left(x\right)=\:x^2-4x-c$

$f\left(c\right)=\:c^2-4c-c$

$f(c) = c$

$c=\:c^2-4c-c$

switching the sides

$c^2-4c-c=c$

subtract c from both sides

$c^2-4c-c-c=c-c$

$c^2-6c=0$

$c\left(c-6\right)=0$

Using the zero factor principle

$\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$c=0\quad \mathrm{or}\quad \:c-6=0$

so, the solutions to the quadratic equations are:

$c=0,\:c=6$

Therefore, a nonzero value of c will be:

$c = 6$

5 0

3 years ago

Compare 2/3 and 2/5 right one or both of the fractions so they have the common denominator use greater than less than or equal t

lora16 [44]

Answer:

10/15 & 6/15

Step-by-step explanation:

6 0

3 years ago

A Galapagos cactus finch population increases by half every decade. The number of finches is

Angelina_Jolie [31]

Answer:

The number of fringes at $d=-2$ is given as 20.

Step-by-step explanation:

Question

A Galapagos cactus finch population increases by half every decade. The number of finches is modeled by the expression

where d is the number of decades after the population was measured. Evaluate the expression for d = −2

Given :

The number of finches is modeled by the expression :

⇒ $45\cdot1.5^d$

where $d$ is the number of decades after the population was measured.

To evaluate the expression for d=-2

Solution:

In order to evaluate the given expression to find the number of finches at $d=-2$ , we will plugin $-2$ for $d$ in the expression and simplify it.

Plugging in $d=-2$ in the expression:

⇒ $45\cdot 1.5^{-2}$

Using negative exponent property. [ $a^{-x}=\frac{1}{a^x}$

⇒ $45\cdot \frac{1}{1.5^2}$

⇒ $45\cdot \frac{1}{2.25}$

⇒ $20$ (Answer)

Thus, the number of fringes at $d=-2$ is given as 20.

This means the number of fringes two decades ago was 20.

6 0

3 years ago

Retro Rides is a club for owners of vintage cars and motorcycles. Every year the club gets together for a ride. This year, 53 ve

kari74 [83]

21 cars, 32 motorcycles.
create a system of equations using x for cars and y for motorcycles.
$\left \{ {{x+y=53} \atop {4x+2y=148}} \right.$
multiply the top equation by 2 to prepare for elimination method
$\left \{ {{2x+2y=106} \atop {4x+2y=148}} \right.$
subtract terms
$\left \{ {{2x+2y=106} \atop {-4x-2y=-148}} \right. = (-2x = -42)$
divide both sides by negative 2 to solve for x
x =21
plug in x into original equation to solve for y.
21 + y = 53
subtract both sides by 21
y=32

8 0

3 years ago