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4 years ago

Please help and thank you!!

Mathematics

1 answer:

mart [117]4 years ago

3 0

The correct answer is A) f(x) should be vertically stretched by 1.5.

This is because it is going to be rising at a much faster rate. Therefore, the slope should be more steep, which can only be done by stretching the graph. Moving it up and down would only change the initial amount she had traveled, which should always be 0.

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Ash invests £200 and gets 3% interest per year.<br> How much will she have after 5 years?

Taya2010 [7]

Answer:

£231.85

Step-by-step explanation:

→ Work out the decimal multiplier

( 3 + 100 ) ÷ 100 = 1.03

→ Multiply the initial investment by the multiplier raised to the power of years

200 × ( 1.03 )⁵ = £231.85

6 0

3 years ago

A sample from 16 shortstops was obtained in an effort to determine whether shortstops have higher salaries than other players. T

marissa [1.9K]

Answer:

1.16 to 2.75

Step-by-step explanation:

The mean salary (millions of dollars) for shortstops was 1.95.

$\bar{x}=1.85$

The population mean for all baseball players was 1.85

$\mu = 1.85$

The population standard deviation was 1.61.

$\sigma = 1.61$

Formula of confidence interval : $x-z\times \frac{\sigma}{\sqrt{n}}$ to $x+z\times \frac{\sigma}{\sqrt{n}}$

z at 95% confidence level = 1.96

Substitute the values in the formula

Confidence interval : $1.95-1.96\cdot\frac{1.61}{\sqrt{16}}$ to $1.95+1.96\cdot\frac{1.61}{\sqrt{16}}$

Confidence interval : 1.16 to 2.75

Hence the 95 percent confidence interval for these data is 1.16 to 2.75

8 0

3 years ago

10. Find the values of x and y.

iragen [17]

Answer:

Could you please provide the question?

Step-by-step explanation:

4 0

3 years ago

Evaluate the double integral. . ∫∫ y sqrt(x^2-y^2) dA, R={(x,y)|0≤y≤x, 0≤x≤1}. R. . Please explain

polet [3.4K]

First we will evaluate: ( substitution: u = x² - y², du = - 2 y dy )
$\int\limits^x_0 {y \sqrt{ x^{2} - y^{2} } } \, dy= \\ \frac{-1}{2} \int\limits^x_0 { u^{1/2} } \, du =$
= $\frac{-1}{3} \sqrt{ (x^{2} - y^{2} ) ^{3} }$ ( than plug in x and 0 )
= $- \frac{1}{3} ( \sqrt{( x^{2} - x^{2}) ^{3} } - \sqrt{ (x^{2} -0 ^{2} ) ^{3} }$ =
= 1/3 x³ ( then another integration )
$1/3\int\limits^1_0 { x^{3} } \, dx = 1/3 ( x^{4}/4)}= 1/3 ( 1 ^{4}/4 - 0^{4} /4 )$
= 1/3 * 1/4 = 1/12

4 0

3 years ago

18 What is the y-intercept of the line

vichka [17]

The answer B. Hope this helps!

7 0

4 years ago

Read 2 more answers