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bixtya [17]
3 years ago
13

An increase of 65% followed by a decrease of 35%

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
5 0

Answer:

huh? it would be 30% the instructions are a little unclear

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-6 + (-2) + 5= ? <br><br> Help would really be appreciated!! :)
kvasek [131]

Answer:

-3

Step-by-step explanation:

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3 years ago
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Match the graph of the function with the function rule.
mylen [45]

Answer:

y = 10( {4}^{x} )

Step-by-step explanation:

From the given exponential graph, the y-intercept is (0,10).

The only exponential function that, has this intercept is

y = 10( {4}^{x} )

Because when x=0, we obtain:

y = 10( {4}^{0} )

Simplify:

y = 10(1) = 10

6 0
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Three friends each have a balance of $5,000 on their credit cards with a 25% APR. They've decided that they will not make any ot
egoroff_w [7]

Answer:

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6 0
2 years ago
Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30
TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

-7, -3, 1, 5, . . .

An arithmetic sequence has a constant difference d and is defined by

a_n=a_1+\left(n-1\right)d

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4

\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

d=4

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=-7

as

a_n=a_1+\left(n-1\right)d

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=4\left(n-1\right)-7           ∵ d=4

\mathrm{Arithmetic\:sequence\:sum\:formula:}

n\left(a_1+\frac{d\left(n-1\right)}{2}\right)

\mathrm{Plug\:in\:the\:values:}

n=30,\:\space a_1=-7,\:\spaced=4

=30\left(-7+\frac{4\left(30-1\right)}{2}\right)

=30\left(58-7\right)     ∵  \frac{4\left(30-1\right)}{2}=58

=30\cdot \:51

=1530           ∵  \mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

a_n=4\left(n-1\right)-7

n = 30

\sum _{n=1}^{30}\:4\left(n-1\right)-7

=\sum _{n=1}^{30}4n-11

\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n

=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11

as

\sum _{n=1}^{30}4n=1860

and

\sum _{n=1}^{30}11=330

so

=1860-330

=1530

7 0
4 years ago
Anyone know how to do #41?
KatRina [158]
Power rule. d/dx(x^n) = nx^(n-1)
We can pull the 5 out and multiply it back in later.

d/dx(x^2) = 2x

2(10) = 20*5 = 100
7 0
3 years ago
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