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Anni [7]
3 years ago
11

Where would 3.3333 be on this number line??

Mathematics
1 answer:
kramer3 years ago
8 0

Answer:

right pasted the 3 on the number line

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The diameter of a large lawn ornament in the shape of a sphere is 16 inches. What is the approximate volume of the ornament? Use
Dvinal [7]

Answer: 2143.6\ in.^3

Step-by-step explanation:

Given: The diameter of a large lawn ornament in the shape of a sphere = 16 inches.

Then, the radius of ornament =\frac{16}{2}=8 inches.

We know that the volume of a sphere is given by :-

\text{Volume}=\frac{4}{3}\pi r^3, where r is the radius of a sphere.

Now, the volume of the ornament is given by :-

\text{Volume}=\frac{4}{3}(3.14) (8)^3\\\\\Rightarrow\text{Volume}=\frac{4}{3}\times3.14\times512=2143.57333333\approx2143.6\ in,^3

Hence, the approximate volume of the ornament =2143.6\ in.^3

7 0
2 years ago
Read 2 more answers
Helppppppppp!!!!!!!
balandron [24]

Answer:

= 2.06

I hope I helped you^_^

3 0
2 years ago
Shureka Washburn has scores of 67, 78, 66, and 93 on her
vichka [17]
The answer would be A
5 0
1 year ago
Solve:<br><br> a.x3+x2-8x - 12x+2<br> b. x3-4x2-3x + 18x-3<br> c. x2 + 4x + 4<br> d. x2 - 6x + 9
NeTakaya
<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}

Next, remember that <u>dividing by a number is the same as multiplying by its reciprocal.</u> To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}

Next, factor x² + 2x and -3x - 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

(\frac{f}{g})(x)=\frac{x(x+2)-3(x+2)}{1}\times \frac{x+2}{x-3}

Now you can rewrite it as:

(\frac{f}{g})(x)=\frac{(x-3)(x+2)}{1}\times \frac{x+2}{x-3}

Next, multiply:

(\frac{f}{g})(x)=\frac{(x-3)(x+2)^2}{x-3}

Next, divide:

(\frac{f}{g})(x)=(x+2)^2

And lastly, simplify:

  • A good tip: (x+y)^2=x^2+2xy+y^2

(\frac{f}{g})(x)=x^2+4x+4

<h2>Answer:</h2>

<u>The correct option is C. x² + 4x + 4.</u>

7 0
3 years ago
If two matrices, A and B, are equal, which of the
alexandr402 [8]

If A and B are equal:

Matrix A must be a diagonal matrix: FALSE.

We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:

A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]

Both matrices must be square: FALSE.

We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works

Both matrices must be the same size: TRUE

If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.

For any value of i, j; aij = bij: TRUE

Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.

8 0
3 years ago
Read 2 more answers
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