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zhuklara [117]
3 years ago
14

If 16 cups equals one gallon than one 1/4 gallon equal cups

Mathematics
1 answer:
hoa [83]3 years ago
8 0
Well...this is a proportion problwm. for every 16 cups I have 1 gallon, so I can write that as:

16 cups
-----------
1 gallon

this value will be proportional to 1/4 a gallon equal "so many" cups. let's equal the unknown about of cups to x.

16 cups______ x cups
-----------.... = ..... ----------
1 gallon _____ 1/4 gallons

I can cross multiply to find x.

1 gallon • x cups = 16 cups • 1/4 gallons

16 times 1/4 is the same as 16/4, which equals 4.

1 gallon • x cups = 4 cups gallons

divide both sides by gallons

x cups = 4 cups

so! 1/4 of a gallon equals 4 cups.
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The maximum flying falcon produces is 60/day. Then, the amount of flying bat produced would be:

total= falcon + bat
70= 60+bat
bat= 70-60= 10

The minimum possible cost: falcon * falcon_cost + bat * bat_cost = 60*$8 + 10*$12 = $480+$120= $600
8 0
3 years ago
I NEED THIS ANSWERED FAST WITH WORK PLEASE
Pavel [41]
1 thousand a month would be my guess
3 0
3 years ago
Which of the following best describes the expression 7(y + 5)?
WINSTONCH [101]

Answer:

d The product of a constant factor of seven and a factor with the sum of two terms

Step-by-step explanation:

It's a product, and one of the factors is 7.

Answer:

d The product of a constant factor of seven and a factor with the sum of two terms

8 0
2 years ago
BRAINLIEST!!! PLZZ HELP!! I REALLY NEED THIS RIGHT!!
joja [24]

Answer:

d and b

Step-by-step explanation:

4 0
3 years ago
Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

f' is greater than 0 when the curve is above the x-axis.

f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0.  That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

* Relative maximums at x=1

3 0
3 years ago
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