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artcher [175]
3 years ago
12

TIME REMAININ

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

The numbers could be consecutive odd but they are not integers if they have the sum of 91.

I cannot clarify my answer because you did not provide choices for the statements..

Step-by-step explanation:

Since the sum of three consecutive odd integers had a sum of 91, you should first simplify. Let's test if the numbers are really integers or odd integers at all.

x+(x+2)+(x+4)=91                    

x+x+2+x+4=91 ←Remove parentheses

3x+6=91← Add the same variables together

3x=91-6 ←Move 6 to the other side

3x=85

x= Answer is not an integer...

The numbers could be consecutive odd but they are not integers

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in the diagram,transversal t intersects parallel lines m and n. Classify the given angle pair. then determine each measures.​
professor190 [17]

Answer:

Step-by-step explanation:

Corresponding angles: ∠2=∠ 6  ;  ∠1 = ∠5 ;    ∠4 = ∠8;  ∠3 =∠7

Vertically opposite angles: ∠1 = ∠3;  ∠2 = 4;  ∠5 = ∠7 ;  ∠6 = ∠8

Interior angles : ∠4, ∠3 , ∠6, ∠7

alternate interior angles are equal: ∠3 = ∠5 ;  ∠4 = ∠6

6 0
3 years ago
Given: ABCD parallelogram BK ⊥ AD , AB = 6, AK = 3 Find: m∠A, m∠B, m∠C, m∠D
Troyanec [42]

Answer: Angle A = 60°, angle B = 120°, angle C = 60°, angle D = 120°

Step-by-step explanation: Please refer to the attached diagram for further details.

The question has given the parallelogram ABCD as having side AB measuring 6 units, side AK measuring 3 units and line BK has been drawn perpendicular to line AD. This means line AK forms a right angle at the point where it meets line AD. From the information provided and the figure derived from that, we have right angled triangle ABK with the right angle at point K, line AB equals 6 units and line AK equals 3 units.

Using angle A as the reference angle, line AK is the opposite (side facing the reference angle), line AB is the hypotenuse (line facing the right angle) and line AK is the adjacent (side that lies between the right angle and the reference angle).

Hence, using the trigonometric ratios,

Cos A = adjacent/hypotenuse

Cos A = 3/6

Cos A = 0.5

Checking with the calculator, (that is second function of Cos 0.5)

A = 60

The opposite sides of a parallelogram are equal (that is line AD is parallel to line BC) and therefore opposite angles are equal (that is angle A is equal to angle C).

Similarly, angle B is equal to angle D. However, angles in a quadrilateral equals 360 degrees.

Therefore, angles in parallelogram ABCD is derived as;

A + B + C + D = 360

60 + B + 60 + D = 360

120 + B + D = 360

Subtract 120 from both sides of the equation

B + D = 240

Having known that angle B equals angle D, angles B and D is derived as each half of the value 240

Angle B = 240/2

Angle B = 120

and angle D = 120

Therefore, the angles are;

A = 60, B = 120, C = 60, D = 120

3 0
3 years ago
7x^2 +2× when x = 3?
borishaifa [10]

Answer:

7(3^2) + 2(3).

That equals to 7(9) + 2(3).

That equals to 63 + 6.

That finally equals to 69.

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation h = ?16t + 160t + 12
insens350 [35]

Answer:

The time taken for the flare to hit the ground is approximately 10.7 seconds.

Step-by-step explanation:

Given : Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation h =- 16t^2+ 160t + 120 models the h height at t seconds of the flare.

To find : How long will it take for the flare to hit the ground?

Solution :

The equation  h =- 16t^2+ 160t + 120 models the h height at t seconds of the flare.

The flare to hit the ground when h=0.

Substitute in the equation,

-16t^2+ 160t + 120=0

Applying quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where, a=-16, b=160 and c=120

x=\frac{-160\pm\sqrt{160^2-4(-16)(120)}}{2(-16)}

x=\frac{-160\pm\sqrt{33280}}{-32}

x=\frac{-160\pm 182.42}{-32}

x=\frac{-160+182.42}{-32},\frac{-160-182.42}{-32}

x=−0.70,10.70

Reject the negative value.

Therefore, the time taken for the flare to hit the ground is approximately 10.7 seconds.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title=" \frac{5}{12}" alt=" \frac{5}{12}" align="a
Tasya [4]

Answer:

About 0.417

Step-by-step explanation:

8 0
3 years ago
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