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Anni [7]
3 years ago
12

Is it possible for a line to pass through exactly two quadrants? explain.​

Mathematics
2 answers:
eimsori [14]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

Any line that is parallel to the x or y axis will pass through exactly 2 quadrants. For example

x = 4

This line passes through the first and 4th quadrant.

y = 4

This passes through the 1st and 2nd quadrant

x = - 2

this passes through the 2nd and 3rd quadrant

y = - 5

This passes through the 3rd and 4th quadrant.

7nadin3 [17]3 years ago
4 0
Yes a line can go through more than one according to the points on the graph
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A line contains the points R (-1, 8) S (1, 4) and T (6, y). Solve for y. Be sure to show and explain all work.
Nikitich [7]

Given:

A line contains the points R(-1, 8), S(1, 4) and T(6, y).

To find:

The value of y.

Solution:

Three points are collinear if:

x_1(y_2-y_3)+x_2(y_3-y_2)+x_3(y_1-y_2)=0

A line contains the points R(-1, 8), S(1, 4) and T(6, y). It means, these points are collinear.

-1(4-y)+1(y-8)+6(8-4)=0

-4+y+y-8+48-24=0

2y+12=0

Subtract 12 from both sides.

2y=-12

Divide both sides by 2.

y=\dfrac{-12}{2}

y=-6

Therefore, the value of y is -6.

3 0
3 years ago
Find the distance between (-2,6) and (1,2)
olga nikolaevna [1]

Step-by-step explanation:

label the numbers (x,y) and (x2,y2)

write down the distance formula

replace the xs and ys by the numbers and then solve them

3 0
3 years ago
What is the inverse of the given relation y = 7x² ?
beks73 [17]

Answer:

y = square root(x/7)

Step-by-step explanation:

switch x and y

x = 7y^2

solve for y

x/7 = y^2

square root(x/7) =y

y inverse is

y= square root(x/7)

7 0
3 years ago
Find X<br><br> A. 3<br> B. sqrt6<br> C. 3sqrt3<br> D. 3sqrt2/2
Jet001 [13]

Answer:

B. sqrt 6 is the answer.maja

5 0
3 years ago
Write the slope-intercept form of the equation that passes through the point (4, -2) and is perpendicular to the line y =4x - 1
ExtremeBDS [4]

Answer:

<h2>         y = -¹/₄x - 1</h2>

Step-by-step explanation:

If two lines are perpendicular then the product of theirs slopes is equal -1:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇒    m₁×m₂ = -1

y = 4x - 2   ⇒   m₁=4

4×m₂ = -1        ⇒    m₂ = -¹/₄

The line y=-¹/₄x+b passes through point (4, -2) so the equation:

-2 = -¹/₄×4 + b must be true

-2 = -1 + b

b = -1

Therefore equation in  slope-intercept form:

                                                y = -¹/₄x - 1

4 0
3 years ago
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