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Tanzania [10]
3 years ago
5

Please help and answer these!!!!

Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

1

Step-by-step explanation::))

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help me do pls.If u don't know how to do,pls don't do or else u will be reported.I need it under 25 min thank u <3​
nevsk [136]
F is proportional to 1/x^2
distance = x
A reduction of 25 percent = 0.75x
Let’s put this in place of x
F = 1/(0.75x)^2
And simplify
F = 1/0.5625x^2

So you need to find the percentage increase from 1/x^2 to 1/0.5625x^2

So what does 1/x^2 multiply by to give 1/0.5625x^2

Written as an equation it is y/x^2 = 1/0.5625x^2
Multiply both sides by x^2
y = 1/0.5625
y = 1.778 (rounded to 3 decimal points)

So the decimal multiplier is 1.778 and so the percent increase is approximately 77.8%
8 0
2 years ago
Solve x4 – 17x2 + 16 = 0.<br> Let u =<br> Select all of the zeroes of the function. i i
Soloha48 [4]

Solve \ x^4 - 17x^2 + 16 = 0

To solve this equation , we need to write it in quadratic form

ax^2+bx+c=0

To get the equation in quadratic form we replace x^2 with u

x^2 = u

x^4 - 17x^2 + 16 = 0 can be written as

(x^2)^2 - 17x^2 + 16 = 0, Replace u for x^2

So equation becomes

u^2 - 17u + 16 = 0

Now we factor the left hand side

-16  and -1  are the two factors whose product is +16  and sum is -17

(u-16) (u-1) = 0

u -16 = 0  so u=16

u-1 =0  so u=1

WE assume u = x^2, Now we replace u with x^2

u = 16 so \ it \ becomes \ x^2 =16

Now take square root on both sides , x= +4  and x=-4

u = 1 so \ it \ becomes \ x^2 =1

Now take square root on both sides , x= +1  and x=-1

So zeros of the function are -4, -1, 1, 4


8 0
3 years ago
Read 2 more answers
Assuming x &gt; 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s
ehidna [41]
The answer is <span>104 x times the square root of 5 x 
</span>
<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span>11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245}  *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\  \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\  \\ =11* \sqrt{5}  * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\  \\ &#10;=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\  \\ &#10;=77x* \sqrt{5*x} +27x* \sqrt{5*x}  = \\  \\ &#10;=77x \sqrt{5x} +27x \sqrt{5x} = \\  \\ &#10;=104x \sqrt{5x}
4 0
3 years ago
Read 2 more answers
Can someone explain to me of how to do this?
Alexxandr [17]

Answer:

1) 11

2) 15

Step-by-step explanation:

The bars on the sides of the numbers represent the absolute value/magnitude of the number, so you will need to remove the negative symbol if it is present in front of the number (if it is already a positive number, leave it as it is).

Example:

|-3+2| = |-1|

= 1

Hope this helps :)

4 0
3 years ago
I am stuck on number 6 and 7. It is a two column proof in geometry. Chapter I’m on is isosceles triangle theorems.
ZanzabumX [31]

Answer:On number 6 in the third line it is Given

Step-by-step explanation:


4 0
3 years ago
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