Answer:
(a) Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.
(b) 
Step-by-step explanation:
Given
![f(x) = e^{-4x};\ [0,2]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20e%5E%7B-4x%7D%3B%5C%20%5B0%2C2%5D)
Solving (a); Does the function satisfy M.V.T on the given interval
We have:
![f(x) = e^{-4x};\ [0,2]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20e%5E%7B-4x%7D%3B%5C%20%5B0%2C2%5D)
The above function is an exponential function, and it is differentiable and continuous everywhere
Solving (b): The value of c
To do this, we use:

In this case:
![[a,b] = [0,2]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D%20%3D%20%5B0%2C2%5D)
So, we have:


Calculate f(2) and f(0)

So:


This gives:



Note that:


This implies that:

So, we have:


Divide both sides by -4


Take natural logarithm of both sides


Apply law of natural logarithm

So:

Solve for c

4/7=220/x. multiply 220 by 7 then divide by 4. x=385 square centimeters.
I hope this helps you
1)
a) 18/50
b) 6.1/3=2
c) 9/2.8/3=3.4=12
2)
1 1/2=1.2+1/2=3/2
3 3/4=3.4+3/4=15/4
if we can 12 muffins with 3/2 cups
how many muffins with 15/4
?.3/2=12.15/4
?=30 muffins
Answer:
Step-by-step explanation: