14. We can represent 1 as √1 and 2 as √4 and because 1 < 3 < 4, we know that √3 is in between 1 and 2. However, 3 is closer to 4 than it is to 1 so √3 is about 2.

15. Again, 3 is √9 and 4 is √16. 9 < 10 < 16 so √10 is in between 3 and 4, however, since 10 is closer to 9 as it is to 16, we know that √10 is about 3.

16. -4 = -√16 and -5 = -√25, since 16 < 22 < 25, we know that -√22 is in between -4 and -5 but 22 is closer to 25 so the answer is -5.

17. -10 = -√100 and -11 = -√121 so -√120 is in between -10 and -11. Since 120 is closer to 121, the answer is -11.

5 0

3 years ago

Evaluate the expression. [3(15 + 4)^2 + 2(20 + 5)^2]^0 A) 0 B) 1 C) 2 D) 5

ziro4ka [17]

Answer:

1 thus b: is the Answer

Step-by-step explanation:

Simplify the following:

(3 (15 + 4)^2 + 2 (20 + 5)^2)^0

(3 (15 + 4)^2 + 2 (20 + 5)^2)^0 = 1:

Answer: 1

5 0

3 years ago