Even numbers are numbers that can be divisible by 2, so in this case
28, 30, 32, 34, 36, 38
^ are even numbers because they can be divided by 2
Answer: y=-2/5x+2
Solving Steps:
2x+5y=10 - Move the variable to the right
5y=10-2x - Divide both sides by five
y=2-2/5x - Reorder the terms
y=-2/5x+2
Answer:
<u>yes your formula is correct </u>
Step-by-step explanation:
Answer: -2
Step-by-step explanation:
Answer:
![x_1 =2 , x_2=7](https://tex.z-dn.net/?f=x_1%20%3D2%20%2C%20x_2%3D7)
Step-by-step explanation:
Consider the revenue function given by
. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).
![\frac{dR}{dx_1} = -10x_1-2x_2+34 =0](https://tex.z-dn.net/?f=%5Cfrac%7BdR%7D%7Bdx_1%7D%20%3D%20-10x_1-2x_2%2B34%20%3D0)
![\frac{dR}{dx_2} = -16x_2-2x_1+116 =0](https://tex.z-dn.net/?f=%5Cfrac%7BdR%7D%7Bdx_2%7D%20%3D%20-16x_2-2x_1%2B116%20%3D0)
From the first equation, we get,
.If we replace that in the second equation, we get
![-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156](https://tex.z-dn.net/?f=-16%5Cfrac%7B-10x_1%2B34%7D%7B2%7D%20-2x_1%2B116%3D0%3D%2080x_1-2x_1%2B116-272%3D%2078x_1-156)
From where we get that
. If we replace that in the first equation, we get
![x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7](https://tex.z-dn.net/?f=x_2%20%3D%20%5Cfrac%7B-10%5Ccdot%202%20%2B34%7D%7B2%7D%3D%5Cfrac%7B14%7D%7B2%7D%20%3D%207)
So, the critical point is
. We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives and check if the criteria is fulfilled in order for it to be a maximum. We get that
![\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%5E2R%7D%7Bdx_1dx_2%7D%3D%20-2%20%3D%20%5Cfrac%7Bd%5E2R%7D%7Bdx_2dx_1%7D)
![\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5E2R%7D%7Bdx_%7B1%7D%5E2%7D%3D-10%2C%20%5Cfrac%7Bd%5E2R%7D%7Bdx_%7B2%7D%5E2%7D%3D-16)
We have the following matrix,
.
Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is
and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum