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Svetach [21]
3 years ago
12

Eric is swimming along the surface of the sea. He uses positive numbers to represent elevations above the surface of the sea and

negative numbers to represent depths under the surface of the sea. Mark is sitting above Eric and Ariel is diving below Eric. Who could be at an elevation of -3m?
Mathematics
1 answer:
Elza [17]3 years ago
5 0

Answer:

Ariel will be at an elevation of -3 meters.

Step-by-step explanation:

We have been given that Eric is swimming along the surface of the sea. He uses positive numbers to represent elevations above the surface of the sea and negative numbers to represent depths under the surface of the sea.

Since Eric is swimming along the surface of the sea, so his elevation will be 0.

As we are told that Mark is sitting above Eric and Eric uses positive number for elevation above surface of the sea, so Mark's elevation will be positive.

As we are told that Ariel is diving below Eric and Eric uses negative number for elevation below surface of the sea, so Ariel's elevation will be negative.

Therefore, Ariel will be at an elevation of -3 meters.

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A map of a rectangular park has a length of 4 inches and a width of 6 inches. It uses a scale of 1 inch for every 30 Miles. What
MakcuM [25]

Answer:

The actual area 21600 miles²

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- A drawing that shows a real object with accurate sizes reduced or

 enlarged by a certain amount called the scale

- Drawing scale is a ratio between the drawing length and the

 actual length

- To find the actual dimensions from the drawing dimensions use the

  scale drawing

*<em> Lets solve the problem</em>

- A map of a rectangular park has a length of 4 inches and a width

 of 6 inches

∴ The drawing dimensions are:

# length = 4 inches

# width = 6 inches

- The scale of the map is 1 inch foe every 30 miles

∴ The scale drawing is 1 : 30

- To find the actual area find the actual dimensions

∵ The scale drawing is 1 : 30

∵ The length = 4 inches and the width = 6 inches

- By using cross multiplication

∴  1        :        30

   4       :  actual length

   6       :  actual width

∴ Actual length = (4 × 30)/1 = 120

∴ Actual length = 120 miles

∴ Actual width = (6 × 30)/1 = 180

∴ Actual Width = 180 miles

∴ The actual dimensions are 120 miles and 180 miles

∵ The area of any rectangle = length × width

∴ The actual area = 120 × 180 = 21600

∴ The actual area 21600 miles²

5 0
3 years ago
Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
3. Which of the following represents the
Vladimir [108]

Answer:

I should help u am busy strongly with mine

7 0
2 years ago
Winston has just gone grocery shopping. The mean cost for each item in his bag was $2.71. He bought a total of 9 items, and the
sukhopar [10]

The cost of the 9th item is  $3.94

Since the mean cost for the 9 items in his bag was $2.71. Then, the total cost will be: = 9 × $2.71 = $24.39

In order to get the price of the 9th item, we have to calculate the price of all the 8 items given which will be:

$2.01 + $2.20 + $2.68 + $3.59 + $3.12 + $1.64, + $1.75 + $3.46 = $20.45

Therefore, the cost of the 9th item will be:

= $24.39 - $20.45

= $3.94

Read related link on:

brainly.com/question/24562826

3 0
2 years ago
PLEASE HELP ONE QUESTION!!!!!! PLEASEEEEE
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VW=CD since they are congruent figure, so CD=6
7 0
2 years ago
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