The transformation which is represented is a 180 degree rotation about the origin
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The filling in of the formula for the n-th term is pretty straightforward. The attachment shows how simple it is.
The 7th term is found by evaluating the expression for n=7.
a₇ = 192
I = p * r * t
264 = p * .06 * 2
264 = .12p
Divide both sides by .12
p = $2200
Answer:
<em>The answer is Hence Proved</em>
Step-by-step explanation:
Given that CB║ED , CB ≅ ED
To prove Δ CBF ≅ Δ EDF
This means that the length of CB is equal to ED
As CB║ED The following conditions satisfies when a transversal cut
two parallel lines
- ∠ EDF = ∠ FBC ( Alternate interior points )
- ∠ DEF = ∠ FCB ( Alternate interior points )
∴ Δ CBF ≅ Δ EDF ( By ASA criterion)
The Δ CBF is congruent to Δ EDF By ASA criterion .
<em> Hence proved </em>
