Given: DC is a diameter of circle k (O). DC ⊥ AB
Prove: AC ≅ BC
1 answer:
Answer:
See explanation
Step-by-step explanation:
Connect points A and O and B and O. Consider two right triangles AOE and BOE. In this triangles,
- AO=BO as circle's radii;
- OE is common leg.
By HL theorem, these triangles are congruent, thus, AC=BC.
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