Answer:
When they are equal, y=y, so we can say:
x^2+5x-2=x+1 subtract x from both sides
x^2+4x-2=1 add 2 to both sides
x^2+4x=3, now add half the linear coefficient squared, (4/2)^2=4
x^2+4x+4=3+4 now the left side is a perfect square
(x+2)^2=7 now take the square root of both sides
x+2=±√7 subtract 2 from both sides
x=-2±√7
x=-2+√7 and -2-√7
y=x+1 the two points where these equations are equal are:
(-2-√7, -1-√7) and (-2+√7, -1+√7)
or approximately:
(-4.65, -3.65) and (0.65, 1.65)
Answer:
y = -2 -5
Step-by-step explanation:
x - 2y = 14
-2y = -x + 14
y = 1/2x - 7
-3 = -2 (-1) + b
-3 = 2 + b
-5 = b
y = -2 -5
Answer:
{-3, 2}U{2, 5}
Step-by-step explanation:
For an equation to be negative, it would need to be in a negative range (below the x-axis or the coordinates are negative y-values). Therefore, we can examine this question and see that the graph is negative when the function crosses the x-axis at -3 and it remains negative until you reach 2 on the x-axis.
Therefore, the first set of negative values is (-3, 2).
Secondly, applying the same logic as before, the function decreases at 2 and then touches the x-axis again at 5. Therefore, the second negative value would be (2, 5).
The negative values are {-3, 2}U{2, 5}.
