Is the graph increasing, decreasing, or constant?

Which of the expressions below has a 1 in the thousandths place of the sum? Select all that apply. A) 32.474 + 16.577 B) 23.452

Paraphin [41]

Answer:

A) 32.474 + 16.577

= 49.051

C) 19.213 + 4.578

= 23.791

Step-by-step explanation:

Place value may be defined as the positional system of a notation where the position of any number with reference to the decimal point determines the value of that number.

A) 32.474 + 16.577

= 49.051

B) 23.452 + 31.561

= 55.013

C) 19.213 + 4.578

= 23.791

D) 8.128 + 9.192

= 17.32

We have to find the expression which contains 1 in the thousandths place in the sum.

We know after the decimal point, the place value are designated as tenths, hundredths, thousandths, and so on.

Therefore, A). 49.051 and C). 23.791 has a place value of 1 in its thousandths place.

6 0

2 years ago

Please help!!!!! I’ll mark you as brainliest!!!!!!

Mademuasel [1]

Answer:

The answer is 7440

5 0

2 years ago

Read 2 more answers

-2{-7-2[3 squared + 2 to the power of 4]-8÷4}

Leto [7]

Answer:

118 i think

Step-by-step explanation:

-2{-7-2[3 squared + 2 to the power of 4]-8÷4}

-2{-7-2{9+16]-2}

-2{-7-50-2}

-2(-59)

118

5 0

2 years ago

What is the mean of this? 48, 12, 35, 57, 42, 15, 74, 29. ILL GIVE U BRAINLYEST

BlackZzzverrR [31]

answer:

48 + 12 + 35 + 57 + 42 + 15 + 74 + 29 = 312

divide by number of numbers,

312 / 8 = 39

the mean is 39.

if correct, please mark the brainliest :)

8 0

2 years ago

The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation

Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

Let X = weights of adult male birds of a certain species

So, X ~ Normal( $\mu=27.5,\sigma^{2} =1.1^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{ X-\mu}{\sigma } }$ ~ N(0,1)

where, $\mu$ = population mean weight = 27.5 grams

$\sigma$ = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

Z score = $\frac{ X-\mu}{\sigma } }$ = $\frac{ 29.37-27.5}{1.1 } }$

= 1.7

4 0

2 years ago