Let
be the set of all students in the <u>c</u>lassroom.
Let
and
be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.
We're given




i. We can split up
into subsets of students that pass both physics and math
and those that pass only physics
. These sets are disjoint, so

ii. 9 students fails both subjects, so we find

By the inclusion/exclusion principle,

Using the result from part (i), we have

and so the probability of selecting a student from this set is

Answer:
The graph should have a y-intercept of -8
Step-by-step explanation:
It seems like your question is incomplete, i can't see any options of graphs.
Answer:
42
Step-by-step explanation:
a = 2, b = 5, and c = 1
- a*(4b + c²) = ⇒ plug in values
- 2*(4*5 + 1²) = ⇒ solving exponents
- 2*(20 + 1) = ⇒ parenthesis
- 2*21 = ⇒ multiplication
- 42 ⇒ answer
the answer is 90000 or 9e+4. hope I helped!
Use the distributive property.
(3/8)*(16x-24)=(3/8)(16x)-(3/8)(24)
16x*3/8=48x/8=6x
24*3/8=72/8=9
6x+9
Hope this helps!