This will only have one solution because it does not deal with a quadratic. Then to isolate x you need to get the similar terms on different sides by subtracting or adding, Then divide both sides by the number next to x (coefficient).
Answer: Experimental probability
Step-by-step explanation:
There are two kinds of probability: Theoretical probability and Experimental probability.
To calculate theoretical probability we divide favorable outcomes by total outcomes.
To calculate experimental probability we divide number of times an event occurs by the total number of trials or times the activity is performed.
Here, A child gets 20 heads out of 30 tosses of a coin. If he declared the chance of getting a head with that coin were 2/3, which is dependent on the activity he performed, thus it is an experimental probability.
Answer:
m>7 = 142°
Step-by-step explanation:
m>6 = 38°
180° - 38° = 142°
m>7 = 142°
Answer:
35/3x +200 = # of calories
Step-by-step explanation:
35/3 = calories burnt in 1 minute
x = minutes exercised for
add 200 to account for calories eaten
35/3x +200 = y
So, I came up with something like this. I didn't find the final equation algebraically, but simply "figured it out". And I'm not sure how much "correct" this solution is, but it seems to work.
![f(x)=\sin(\omega(x))\\\\f(\pi^n)=\sin(\omega(\pi^n))=0, n\in\mathbb{N}\\\\\\\sin x=0 \implies x=k\pi,k\in\mathbb{Z}\\\Downarrow\\\omega(\pi^n)=k\pi\\\\\boxed{\omega(x)=k\sqrt[\log_{\pi} x]{x},k\in\mathbb{Z}}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csin%28%5Comega%28x%29%29%5C%5C%5C%5Cf%28%5Cpi%5En%29%3D%5Csin%28%5Comega%28%5Cpi%5En%29%29%3D0%2C%20n%5Cin%5Cmathbb%7BN%7D%5C%5C%5C%5C%5C%5C%5Csin%20x%3D0%20%5Cimplies%20x%3Dk%5Cpi%2Ck%5Cin%5Cmathbb%7BZ%7D%5C%5C%5CDownarrow%5C%5C%5Comega%28%5Cpi%5En%29%3Dk%5Cpi%5C%5C%5C%5C%5Cboxed%7B%5Comega%28x%29%3Dk%5Csqrt%5B%5Clog_%7B%5Cpi%7D%20x%5D%7Bx%7D%2Ck%5Cin%5Cmathbb%7BZ%7D%7D)
