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3 years ago

Find the value of x (x−9/3)=2

Mathematics

2 answers:

Artist 52 [7]3 years ago

8 0

Answer:

x = 5

Step-by-step explanation:

I hope this helps you! :D

Alla [95]3 years ago

4 0

Answer:

(x−9/3)=2 x = 5

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How do i solve thisx/12= 0

Elis [28]

Answer:

Step-by-step explanation:

0÷12=0

The way to figure this problem out is to multiply 0 by 12 and than you get 0.

7 0

3 years ago

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A 2 foot wide painting should be centered on a 14 foot wide wall. How many feet (x) should be on each side of the painting?

geniusboy [140]

Divide the length of the wall by 2 to find the center of the wall:14/2 = 7 feet

The center of the painting is 2/2 = 1 foot.

The edge of the wall would be the center of the wall minus the center of the painting:

7 - 1 = 6 feet.

There should be 6 feet on each side of the painting.

4 0

3 years ago

Are these correct? If not please help me write the correct answer.

Keith_Richards [23]

Answer:

Mostly correct

For Q3, you are doing great, you remembered that negative numbers can happen if the exponent is an odd number.

For Q4, I think you were confused with the fractions,

4(i)

$(\frac{2}{3} )^{4} = (\frac{2^{4}}{3^{4}}) = (\frac{16}{81}) =0.198$

4(ii) is also wrong but I'll let you try to fix it yourself following what I given you for 4(i). You should get 1/64

Hope this helps!

4 0

3 years ago

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The volume of this rectangular solid is?

Maru [420]

Well, volume is: length x width x height

so, 5 x 14 x 8= 560 inches

8 0

3 years ago

Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f

vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

$f(x)=ax^3+bx^2+cx+d$

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

$y = x^3 - x$

Equate y to 0

$x^3 - x = 0$

Expand

$x(x^2 - 1) = 0$

Express $x^2 - 1$ as difference of two squares

$x(x - 1)(x +1 ) = 0$

x = 0 or 1 or -1

For 2 x intercepts

$y = x^3 - x$

$y =(x-5)^2)(x+7)$

Equate y to 0

$(x-5)^2(x+7) = 0$

Expand

$(x-5)(x-5)(x+7) = 0$

x= 5 or x = -7

For 1 x intercept

$y = x^3$

Equate y to 0

$x^3 = 0$

Take cube roots of both sides

$x = 0$

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

$y = x^2 + x + 17$

The above function has no x intercept.

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

$y = x^2- 6x + 9$

Equate y to 0

$x^2- 6x + 9 = 0$

Expand

$x^2 - 3x - 3x + 9 = 0$

$(x - 3)(x-3) = 0$

$x = 3$

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0

2 years ago