<em><u>Question:</u></em>
Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.
The complete figure of this question is attached below
<em><u>Answer:</u></em>
<h3>The perimeter of the quadrilateral is 129 inches</h3>
<em><u>Solution:</u></em>
The complete figure of this question is attached below
Given that, a quadrilateral with,
Side lengths are:

The values of the side lengths when x = 2 are

Perimeter of a quadrilateral = Sum of its sides
Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches
Thus perimeter of the quadrilateral is 129 inches
Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
Answer: 3
Step-by-step explanation:
45 / 3 = 15
So,
What times 5 = 15
The answer is 3.
Answer:
324 and 144
Step-by-step explanation:
We require
a₁, a₂, a₃, a₄
where a₂ and a₃ are the required geometric means
The n th term of a geometric sequence is
= a₁
where a₁ is the first term and r the common ratio
Here a₁ = 729 and a₄ = 64, thus
729(r³) = 64 ( divide both sides by 729 )
r³ =
( take the cube root of both sides )
r =
=
, then
a₂ = 729 ×
= 81 × 4 = 324
a₃ = 324 ×
= 36 × 4 = 144
Thus
729, 324, 144, 64