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Goryan [66]
3 years ago
9

Find the sum of the numbers divisible by 7 between 30 and 500

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

17822

Step-by-step explanation:

The number that are divisible by 7 between 30 and 500 are as follows :

35, 42,49,.....,497

It will form an AP with first term, a = 35 and common difference, d = 7

Let there are n terms in the AP.

nth term of an AP is given by :

a_n=a+(n-1)d

Putting all the values,

497=35+(n-1)7\\\\462=(n-1)7\\\\n-1=66\\\\n=67

Now, the sum of n terms of an AP is given by :

S_n=\dfrac{n}{2}[2a+(n-1)d]

Putting all the values,

S_n=\dfrac{67}{2}[2(35)+(67-1)7]\\\\S_n=17822

Hence, the sum of the numbers that are divisible by 7 between 30 and 500 is 17822.

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P=0.4125

Step-by-step explanation:

In this case we have a uniform probability. In the graph the horizontal axis represents the possible values of the variable x and the vertical axis represents the probability P(x).

To calculate the probability that x is between 4.71 and 7.4 we calculate the area under the curve.

The horizontal length between 4.71 and 7.4 is:

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