The probability in all given conditions is 1/4.
According to the statement
Number of coin tossed = 3
Total outcomes = 8
Now, we have to find the probabilities on different conditions.
- Probability of a head on each of the last two tosses
Probability = A head on each of the last two tosses/ total outcomes
Probability = 2/8
Probability = 1/4.
- Probability of alternating tale and head
Probability = alternating tale and head / total outcomes
Probability = 2/8
Probability = 1/4.
- Probability of a no tails on each of the last two tosses
Probability = A No tails on each of the last two tosses/ total outcomes
Probability = 2/8
Probability = 1/4.
So, The probability in all given conditions is 1/4.
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Answer:
6-16y
Step-by-step explanation:
2(3-8y)
3(2)-8y(2)
6-16y
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Answer:
Cash, Bonds, Stocks and Mutual funds
Step-by-step explanation:
The four major categories of securities are:
- Cash
- Bonds
- Stocks
- Mutual funds
These 4 major categories are evaluated as given below:
- Cash: Cash is your normal money. You can use it to buy your everyday goods and services or invest in cash in various asset classes.
- Bonds: Bond is debt instrument and bonds are the agreement of debt. and bonds carry coupon rate that is (interest equivalent), tenure and final capital repayment
- Stocks: Ownership of stock in a company. A group (or a single) share of any company is called stock. Stock means you have some stake in the company.
- Mutual Funds: A mutual fund is an asset basket that can hold cash, bonds, stocks, real estate, and so on. The type and structure of mutual funds will vary depending on the client's choice of the fund manager and the category of the category
Answer:
Step-by-step explanation:
<u>We observe the pattern:</u>
<u>It can be put as:</u>
- 0 + 1, 1 + 4, 4 + 9, 9 + 16, ..
or
- 0² + 1², 1² + 2², 2² + 3², 3² + 4², ..
<u>The nth term is going to be:</u>
<u>The sum of the 31 terms will be:</u>
- N = 0² + 1² + 1² + 2² + 2² + 3² + 3² + ... + 30² + 30² + 31²
or
- N = 2(1² + 2² + 3² + ... + 30²) + 31²
<u>Use the formula for sum of the first n squares:</u>
- 1² + 2² + 3² + ... + n² = n(n + 1)(2n + 1)/6
<u>The sum N equals:</u>
- N = 2(30*31*61)/6 + 31² = 10*31*61 + 31²
<u>And the value of N/31 is:</u>
