<span>You get a roaring friar place!</span>
Using
f1(x)= -x=3t =14
with f2(x) as x=4y
f1(f2)= -x-3y=14
F1(4y)= -(4y)-3y=14
= -4y-3y=14
= - 7y=14
= y= -2
Using the value of y, solve fo rx by entering the value in the original form of f1 or f2
<span>-x-3y=14</span>
-x-3(-2)=14
-x+6=14
x=-8
OR
x=4y
=4(-2)
= -8
Thus the solution is (x,y) = (-8,-2)
Answer:
I think it is (36-6)+4 because it says 6 less than the quotient of 36 so it is 36-6 and 4 so it becomes +4 and the answer is (36-6)+4
