Write an equation of line in standard form with a slope of 3 through the point (9,-4)

1 answer:

8 0

Hi there!
We are told to write an equation of a line in standard form with a slope for 3 that goes through the point (9,-4). There are many ways to do this, but the easiest one would be using the point-slope form. This is the point-slope form:
$y-y _{1} =m(x-x _{1} )$
If we let m = 3, y1 = -4, x1 = 9, we can substitute the values back into the equation to get: $y-(-4)=3(x-9 )$ . We can simplify the equation to get $y + 4 = 3x - 27$ . Now, we combine like terms by subtracting 4 from both sides, giving us y = 3x - 31. Finally, we subtract 3x from both sides to get -3x + y = -31. Therefore, the answer to your query is -3x + y = -31.

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