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patriot [66]
3 years ago
15

Write an equation of line in standard form with a slope of 3 through the point (9,-4)

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0
Hi there!
We are told to write an equation of a line in standard form with a slope for 3 that goes through the point (9,-4). There are many ways to do this, but the easiest one would be using the point-slope form. This is the point-slope form:
y-y _{1} =m(x-x _{1} )
If we let m = 3, y1 = -4, x1 = 9, we can substitute the values back into the equation to get: y-(-4)=3(x-9 ). We can simplify the equation to get y + 4 = 3x - 27. Now, we combine like terms by subtracting 4 from both sides, giving us y = 3x - 31. Finally, we subtract 3x from both sides to get -3x + y = -31. Therefore, the answer to your query is -3x + y = -31.
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Answer:

1. x = -4y ---> y = (-1/4)x

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Step-by-step explanation:

1. Re-write your equation so that x is on the right and y is on the left:

x = -4y ---> y = (-1/4)x

slope = -1/4. y-intercept = (0,0)

2. y-intercept = (0,4) ----> P1

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