<u>Question 8</u>
a^2 + 7a + 12
= (a+3)(a+4)
When factorising a quadratic, the product of the two factors should equal the constant term (12), and the sum of the two factors should equal the linear term (7). To find the two factors, list out the factors of 12 (1x12, 2x6, 3x4) and identify the pair that adds up to 7 (3+4).
An alternative method if you get stuck during your exam would be to solve it algebraically using the quadratic formula and then write it in the factorised form.
a = (-7 +or- sqrt(7^2 - 4(1)(12)) / 2(1)
= (-7 +or- sqrt(1))/2
= -3 or -4
These factors are the negative of the values that would go in the brackets when written in factorised form, as when a = -3 the factor (a+3) would equal 0. (If it were positive 3 instead, then in the factorised form it would be a-3).
<u>Question 10</u>
-3(x - y)/9 + (4x - 7y)/2 - (x + y)/18
Rewrite each fraction with a common denominator so you can combine the fractions into one.
= -6(x - y)/18 + 9(4x - 7y)/18 - (x + y)/18
= (-6(x - y) + 9(4x - 7y) - (x + y)) /18
Expand the brackets and collect like terms.
= (-6x + 6y + 36x - 63y - x - y)/18
= (29x - 58y)/18
= 29/18 x - 29/9 y
Answer:
5c
Step-by-step explanation:
5c is the only value you can take out of both factors
Answer:
Functions are linearly dependent (are not linearly independent.)
Step-by-step explanation:
Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation
is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.
Now, let f(x), g(x) and h(x) be the functions:
Then, letting α = 1, β= -1 and ω = -2, we see that:
Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.
Answer:
$0.41
Step-by-step explanation:
4.92 ÷ 12 = .41 (Look at drawing)
Answer: 2/125
Step-by-step explanation: No esto 100% seguro pero hice esto:
2/5 % 4 = 2/125
