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Rzqust [24]
3 years ago
14

Find the equation of the line Y= __x + __

Mathematics
1 answer:
SpyIntel [72]3 years ago
5 0

Answer:

Step-by-step explanation:

(0, -9) and (3,3)

(3+9)/(3-0) = 12/3 = 4

y + 9 = 4(x - 0)

y + 9 = 4x - 0

y = 4x - 9

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Darren has a wooden board that is Three-fifths of a meter long. He cuts the board into 3 equal parts. How long is each section o
Alik [6]

Answer:

Each section of the board is 1/3 or 0.334(0.333333333333) of a meter

Step-by-step explanation:

3/5 divided by 3 is the equation we have to do.

3/5 divided by 3 is also equal to 3/5 times the reciprocal of 3 or 1/3

3/5 * 1/3

3*1 = 3

5*3 = 15

3/15 which can simplify to 1/3. (divide numerator and denominator by 3.)

Each section of the board is 1/3 or 0.334(0.333333333333) of a meter

8 0
3 years ago
25+ -8 equals I really need help
Nimfa-mama [501]

Answer:

17

Step-by-step explanation:

Saying 25+ -8 is basically saying 25-8, and since 25 is the bigger number and it's positive, you get positive 17

7 0
3 years ago
Read 2 more answers
A grocery store manager claims that 75% of shoppers purchase bananas as least once a month. Technology was used to simulate choo
Keith_Richards [23]

Answer:

P-value = 0.0333

At 5% level of significance;

0.0333 < 0.05

Therefore, we reject null hypothesis H₀ at 5% level of significance,

We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated

 

Step-by-step explanation:

 Given the data in the question;

To test whether population proportion p is overstated;

Null hypothesis H₀ : p = (75%) = 0.75

Alternative hypothesis H₁ : = < (75%) < 0.75

now, sample proportion p" = 64 / 100 = 0.64

from the dot plot below, we will determine the p-value for test { P(p" < 0.64)}

so, the number of times p"<0.64 in 150 simulations is 5

Hence; P(p" < 0.64 ) = 5 / 150 = 0.0333

P-value = 0.0333

At 5% level of significance;

0.0333 < 0.05

Therefore, we reject null hypothesis H₀ at 5% level of significance,

We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated

7 0
3 years ago
Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down
Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}

10C2*15C1=675

2. Choose 3 Comedies from the 10. This is calculated as:

10C3=\frac{10!}{3!(10-3)!}=120

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

8 0
3 years ago
HELP!! Can anyone answer this?
olya-2409 [2.1K]
I think that it is d
5 0
3 years ago
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