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pshichka [43]
3 years ago
12

Type the correct answer in the box use numerals instead of words if necessary use / for the fraction bar

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
3 0

If you use the polynomial remainder theorem, right away you get a remainder of

h(-3)=(-3)^4+(-3)^2-2=88

bonufazy [111]3 years ago
3 0

Answer: The remainder would be 88.

Step-by-step explanation:

Since we have given that

f(h)=h^4+h^2-2

and

g(h)=h+3

We need to find the remainder while dividing f(h) by g(h).

First we take, g(h) = 0

h+3=0\\\\h=-3

Now, we put the value of h = -3 in f(h) to get the remainder.

f(-3)=(-3)^4+(-3)^2-2\\\\f(-3)=81+9-2\\\\f(-3)=90-2\\\\f(h)=88

Hence, the remainder would be 88.

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Answer:

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hope this helped!

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John can type 2/3 of a manuscript in 12 hours. If he is joined by Laura, they can complete the typing in 2 hours. How many hours
Sonja [21]
Hello there,

1/18 + 1/x = 1/2 
<span>1/x = 9/18 - 1/18 </span>
<span>1/x = 8/18 = 4/9 </span>
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Find the coefficient of x² in the expansion of (x - 2/x)⁶
Snowcat [4.5K]

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I think answer for ur question is 60

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At one point the average price of regular unleaded gasoline was ​$3.41 per gallon. Assume that the standard deviation price per
Aleonysh [2.5K]

Answer:

a)  1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75

So we expected about 75% within two deviations from the mean

b) 1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

Lower = 3.41 -1.5*0.09 = 3.275

Upper = 3.41 +1.5*0.09 = 3.545

c) We can calculate how many deviations we are within the mean with the limits with this formula:

z =\frac{x-\mu}{\sigma}

And using the lower limit we got:

z = \frac{3.05-3.41}{0.09}=-4

And with the upper limit we got:

z = \frac{3.77-3.41}{0.09}=4

So then the value of k =4 and the percentage is given by:

1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375

Step-by-step explanation:

Previous concepts and Data given  

\mu =3.41 reprsent the population mean

\sigma=0.09 represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: 1-\frac{1}{k^2}

Part a

For this case we can find the percentage required replaincg k =2 and we got:

1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

Lower = 3.41 -1.5*0.09 = 3.275

Upper = 3.41 +1.5*0.09 = 3.545

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

z =\frac{x-\mu}{\sigma}

And using the lower limit we got:

z = \frac{3.05-3.41}{0.09}=-4

And with the upper limit we got:

z = \frac{3.77-3.41}{0.09}=4

So then the value of k =4 and the percentage is given by:

1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375

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