Answer:
I need more info.
Step-by-step explanation:
Answer:
m∠BOC = 40°
Step-by-step explanation:
Given O A ‾ ⊥ O C ‾ OA ⊥ OC m∠BOC=6x−6 ∘
m∠AOB=5x+8 ∘
Find m ∠ B O C:
This means that: m∠BOC and m∠AOC intersect at a right angle.
Hence:
m∠BOC + m∠AOC = 90°
Step 1
Solving for x
6x - 6 + 5x + 8 = 90°
11x -2 = 90°
11x = 90 - 2
11x = 88
x = 88/11
x = 8
Step 2
Solving for m∠BOC
m∠BOC = 6x - 8
m∠BOC = 6(8) - 8
= 48 - 8
= 40°
Answer:
13x/15-6
Step-by-step explanation:
i used symlobab
So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)
Hope this helps!
Answer:
3
Step-by-step explanation:
trust me