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3 years ago

Determine the rigid transformations that will map ΔABC to ΔXYZ.

Mathematics

2 answers:

Luba_88 [7]3 years ago

5 0

Solution: The correct option is d, i.e., Translate vertex X to vertex A; rotate ΔXYZ to align the sides and angles.

Explanation:

we know that the sum of angles of a triangle is always $180^{\circ}$ . In ΔXYZ,

$\angle X +\angle Y +\angle Z=180^{\circ}$

$35^{\circ} +\angle Y +47^{\circ}=180^{\circ}$

$\angle Y +82^{\circ}=180^{\circ}$

$\angle Y =98^{\circ}$

In both triangles it is noticed that the sides AC and XZ are equal. In given triangles $\angle A =\angle X=35^{\circ}$ and $\angle B =\angle Y=98^{\circ}$ .

By AAS rule of congruence ΔABC and ΔXYZ are congruent triangles, therefore we can transform ΔABC to ΔXYZ. For the transformation of ΔABC to ΔXYZ translate the vertex having same angle and rotate the triangle to align the sides and angles.

Since vertex X and vertex A have same angle, therefore we translate vertex X to vertex A and rotate ΔXYZ to align the sides and angles.

Hence the correct option is d.

Bond [772]3 years ago

3 0

On E2020 , the correct answer is D

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3 years ago

Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

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4 years ago

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Step-by-step explanation:

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3 years ago

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Answer:

Step-by-step explanation:

Given the expression 2n²(n-2) - a(n-2), to write this expression in a complete factor form, simply follow the instruction;

Let's assume the original expression has been broken down into that form in question, if we look at both terms, we will see that n-2 in parenthesis is common to both terms, we can therefore factor out n-2 from both terms as shown;

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= n-2(2n² - a)

Hence the complete factor form of the expression is (n-2)(2n² - a) because the expression cannot be simplified any further.

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